在Python中读取二进制文件（.chn）

Question

在python中，如何读取二进制文件（这里需要读取.chn文件）并以二进制格式显示结果？

Answer 1

Assuming that values are separated by a space:

with open('myfile.chn', 'rb') as f:
    data = []
    for line in f:  # a file supports direct iteration
        data.extend(hex(int(x, 2)) for x in line.split())

In Python is better to use open() over file() , documentation says it explicitly:

When opening a file, it's preferable to use open() instead of invoking the file constructor directly.

rb mode will open the file in binary mode.

Reference:
http://docs.python.org/library/functions.html#open

Answer 2

try this:

    with open('myfile.chn') as f:
        data=f.read()
        data=[bin(ord(x)).strip('0b') for x in data]
        print ''.join(data)

and if you want only the binary data it will be in the list.

    with open('myfile.chn') as f:
        data=f.read()
        data=[bin(ord(x)).strip('0b') for x in data]
        print data

In data now you will have the list of binary numbers. you can take this and convert to hexadecimal number

Answer 3

with file('myfile.chn') as f:
  data = f.read()   # read all strings at once and return as a list of strings
  data = [hex(int(x, 2)) for x in data]  # convert to a list of hex strings (by interim getting the decimal value)