将结构指针传递给函数时出错“ISO C禁止转发参数去除”？

Question

I have the following code, the struct declaration is before the main, so is the function declaration

struct stuff{
        int sale_per_day[Kdays];
        int max_sale;
        };

void set_max();

and that part is in the end...

void set_max(struct stuff *point; int n = 0)
{
return;
}

Now what exactly am I doing wrong? I get the

"ISO C forbids forward parameter declaration"

error. I am working with GCC C89 as per the course demands.

Answer 1

它看起来好像只需要一个逗号而不是分号：

void set_max(struct stuff *point, int n = 0)

Answer 2

There are a few issues with your code snippet:

void set_max(struct stuff *point; int n = 0)

1) Your prototype does not match the definition. C usually complains about that
2) You definition contains a semicolon where it should be a comma
3) I don't think int n = 0 is allowed in the parameter list either.

Please try the following.

struct stuff {
    int sale_per_day[Kdays];
    int max_sale;
};

void set_max(struct stuff *point);

and

void set_max(struct stuff *point)
{
    int n = 0;
    return;
}