[英]How to instantiate object of $this class from within the class? PHP
I have a class like this: 我有一个这样的课:
class someClass {
public static function getBy($method,$value) {
// returns collection of objects of this class based on search criteria
$return_array = array();
$sql = // get some data "WHERE `$method` = '$value'
$result = mysql_query($sql);
while($row = mysql_fetch_assoc($result)) {
$new_obj = new $this($a,$b);
$return_array[] = $new_obj;
}
return $return_array;
}
}
My question is: can I use $this in the way I have above? 我的问题是:我可以像上面一样使用$ this吗?
Instead of: 代替:
$new_obj = new $this($a,$b);
I could write: 我可以写:
$new_obj = new someClass($a,$b);
But then when I extend the class, I will have to override the method. 但是当我扩展类时,我将不得不重写该方法。 If the first option works, I won't have to. 如果第一个选项有效,则无需这样做。
UPDATE on solutions: 解决方案更新:
Both of these work in the base class: 这些都在基类中起作用:
1.) 1.)
$new_obj = new static($a,$b);
2.) 2.)
$this_class = get_class();
$new_obj = new $this_class($a,$b);
I have not tried them in a child class yet, but I think #2 will fail there. 我还没有在儿童班上尝试过它们,但是我认为#2在那里会失败。
Also, this does not work: 另外,这不起作用:
$new_obj = new get_class()($a,$b);
It results in a parse error: Unexpected '(' It must be done in two steps, as in 2.) above, or better yet as in 1.). 它会导致解析错误:意外的'('必须分两步完成,如上面的2.)所述,或者更好的是如1.)所述。
Easy, use the static
keyword 简单,使用static
关键字
public static function buildMeANewOne($a, $b) {
return new static($a, $b);
}
See http://php.net/manual/en/language.oop5.late-static-bindings.php . 参见http://php.net/manual/en/language.oop5.late-static-bindings.php 。
You may use ReflectionClass::newInstance 您可以使用ReflectionClass :: newInstance
http://ideone.com/THf45 http://ideone.com/THf45
class A
{
private $_a;
private $_b;
public function __construct($a = null, $b = null)
{
$this->_a = $a;
$this->_b = $b;
echo 'Constructed A instance with args: ' . $a . ', ' . $b . "\n";
}
public function construct_from_this()
{
$ref = new ReflectionClass($this);
return $ref->newInstance('a_value', 'b_value');
}
}
$foo = new A();
$result = $foo->construct_from_this();
Try using get_class(), this works even when the class is inherited 尝试使用get_class(),即使继承了该类,此方法也有效
<?
class Test {
public function getName() {
return get_class() . "\n";
}
public function initiateClass() {
$class_name = get_class();
return new $class_name();
}
}
class Test2 extends Test {}
$test = new Test();
echo "Test 1 - " . $test->getName();
$test2 = new Test2();
echo "Test 2 - " . $test2->getName();
$test_initiated = $test2->initiateClass();
echo "Test Initiated - " . $test_initiated->getName();
When running, you'll get the following output. 运行时,您将获得以下输出。
Test 1 - Test 测试1-测试
Test 2 - Test 测试2-测试
Test Initiated - Test 测试启动-测试
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