旧样式类，新样式类和元类

Question

In Python 2.x, all new-style classes inherit from object implicitly or explicitly. Then look at this:

>>> class M(type):
...     pass
...
>>> class A:
...     __metaclass__ = M
...
>>> class B:
...     pass
...
>>> a = A()
>>> b = B()

>>> type(A)
<class '__main__.M'>
>>> type(a)
<class '__main__.A'>

Does this mean A is a new-style class? But A doesn't inherit from object anyway, right?

>>> type(B)
<class 'classobj'>
>>> type(b)
<type 'instance'>

OK, B is a classic class, isn't it?

>>> isinstance(A, object)
True
>>> isinstance(B, object)
True

why are instances of both A and B instances of object ?

If B is an instance of object , then type(B) wouldn't be classobj , right?

Answer 1

About metaclasses you may read here: http://docs.python.org/reference/datamodel.html#customizing-class-creation . Generally metaclasses are intended to work with new style classes. When you write:

class M(type):
    pass

and you use:

class C:
    __metaclass__ = M

you will create a new style object because the way M is defined (default implementation uses type to create a new-style class). You could always implement you own metaclass that would create old-style classes using types.ClassType .

Answer 2

About slots you may read here http://docs.python.org/release/2.5.2/ref/slots.html , a fragment:

By default, instances of both old and new-style classes have a dictionary for attribute storage.

For new-style classes you may add __slots__ , then the per-object dictionary will not be created.