指定一个class成员function为另一个class的好友？

Question

According to the C++ Primer book, the author mentioned that we can specify a class member function as a friend of another class, instead of the entire class (page 634).

Then, I tested this code:

class A
{
public:
    friend void B::fB(A& a);
    void fA(){}
};
class B
{
public:
    void fB(A& a){};
    void fB2(A& a){};
};

I just wanted the fB() to be friend of class A , not the entire class B . But the above code produced an error: 'B': is not a class or namespace name . (I am using Visual C++ 2005)

Answer 1

Try putting the B definition before A's:

class A; // forward declaration of A needed by B

class B
{
public:
    // if these require full definition of A, then put body in implementation file
    void fB(A& a); // Note: no body, unlike original.
    void fB2(A& a); // no body.
};

class A
{
public:
    friend void B::fB(A& a);
    void fA(){}
};

A needs the full definition of B . However, B needs to know about A , but does not need the full definition, so you need the forward declaration of A .

Answer 2

When the compiler starts compiling the code( usually from top ) and it encounters this line:

friend void B::fB(A& a);

1. at this point, compiler has no idea about type info of B so it throws an error ( 'B' : is not a class or namespace name ).

2. by forward declaration of class B, compiler knows about type of B is Class in advance to its actual declaration with all members.

3. run below code after forward declaration of class B.

///////////////

class B;
class A
{
public:
    friend void B::fB(A& a); 
    void fA(){};
};
class B
{
public:
    void fB(A& a){};
    void fB2(A& a){};
};

Still error !!!

because forward declaration is just a declaration of an identifier for which the programmer has not yet given a complete definition. so compiler needs full definition of B before class A.

Note: class A definition dependents on type of B and also definition of B (ie B::fB) so that forward declaration alone can not resolve, complete definition of class B needs to define before class A.

4 run this code

////////

class B
{
public:
    void fB(A& a){};
    void fB2(A& a){};
};
class A
{
public:
    friend void B::fB(A& a); 
    void fA(){}
};

Still error !!!

because class B member functions fB & fB2 having arguments of type A but compiler has no idea about type info of A so by forward declaration of class A, we can let compiler knows about type info of A. Note: class B definition only dependent on type of A not the members of A so that forward declaration of A resolve step 4.

5. final code

////////////////////////

class A;  // forward declaration of A needed by B
class B
{
public:
    void fB(A& a);
};

class A
{
    int i;
public:
    friend void fA(A& a);    //specifying function fA as a friend of A, fA is not member function of A
    friend void B::fB(A& a); //specifying B class member function fB as a friend of A
};

// fA is Friend function of A
void fA(A& a)
{
    a.i  = 11; // accessing and modifying Class A private member i
    cout<<a.i<<endl;
}

// B::fB should be defined after class A definition only because this member function can access Class A members
void B::fB(A& a)
{
    a.i  = 22; // accessing and modifying Class A private member i in Class B member function fB
    cout<<a.i<<endl;
}

int main()
{
    A a;
    fA(a);    // calling friend function of class A

    B b;
    b.fB(a);  // calling B class member function fB, B:fB is friend of class A

    return 0;
}

6 Exercise:

// Cyclic dependency 
#include<iostream>
using namespace std;

class A;

class B
{
public:
    void fB(A& a);
    friend void A::fA(B& b); //specifying class A's member function fA as a friend of B
};

class A
{
    int i;
public:
    void fA(B& b);  
    friend void B::fB(A& a); //specifying class B's member function fB as a friend of A
};

int main()
{
    return 0;
}

Answer 3

For this to work, the full definition of B needs to be known before the definition of A .

So forward declare A , since B doesn't need the full type, and switch the definitions around:

class A;
class B
{
public:
    void fB(A& a){};
    void fB2(A& a){};
};
class A
{
public:
    friend void B::fB(A& a);
    void fA(){}
};

Answer 4

When the compiler starts reading the code( usually from top ) and it encounters this line:

friend void B::fB(A& a);

Then compiler doesn't understand what do you mean by this B:: . Even if you have defined this class later in the code but compiler doesn't know that. So it's usually a good to practice to do forward declaration of class( class Name; ) if the definition resides later in the code.

Answer 5

firstly forward declare class A, so that its visible in class B definition. then define class A containing a friend function from class B.

Answer 6

First of all before using a particular class name you will have to declare it first. So you will need a forward declaration of the Class B as you are using it in Class A before the Class B has been originally declared.

Secondly you will need to define the functions (that are using variables from both the classes- here the friend functions ) after both the classes have been defined. Or else we may face errors.

For example

#include<iostream>

using namespace std;

class alpha1;

class alpha2
{
    public:

        void put_bata(int a,int b);
};

void alpha2 :: put_bata(int a,int b)
{
    alpha1 net;

    net.roll=a;

    net.id=b;

    net.get_data();
}

class alpha1
{
    int roll;

    int id;

    public:

        void get_data(void)
        {
            cout<<roll<<endl<<id<<endl;
        }

        friend void alpha2 :: put_bata(int a,int b);
};

int main()
{
    alpha2 gamma;

    gamma.put_bata(5,6);

    return 0;
}

Will show us errors as put_bata tries to access roll and id before they are defined even if we had a forward declaration of the class but the code given below will just work fine.

#include<iostream>

using namespace std;

class alpha1;

class alpha2
{
    public:

        void put_bata(int a,int b);
};

class alpha1
{
    int roll;

    int id;

    public:

        void get_data(void)
        {
            cout<<roll<<endl<<id<<endl;
        }

        friend void alpha2 :: put_bata(int a,int b);
};

void alpha2 :: put_bata(int a,int b)
{
    alpha1 net;

    net.roll=a;

    net.id=b;

    net.get_data();
}


int main()
{
    alpha2 gamma;

    gamma.put_bata(5,6);

    return 0;
}

Answer 7

@juanchopanza @ipkiss Regarding the problem that you can't access data members of A inside fB(A& a) because A is not defined yet. Instead of defining it in a separate file and including it, you can just define the function fB(A& a) after the definition of class A so that fB(A& a) is able to see data members of A.

Answer 8

#include <iostream>
#include <string>
using namespace std;
 
class Manager;
class Employee;
 
class Admin{
    public:
    void EmployeeDetails(Employee &obj);
    void ManagerDetails(Manager &obj);
};
 
class Employee{
    string name = "praful";
    friend void Admin::EmployeeDetails(Employee &obj);    
};
 
class Manager{
    string name = "Robert";
    friend void Admin::ManagerDetails(Manager &obj);
};
 
 
void Admin::EmployeeDetails(Employee &obj)
{
    cout << "Employee :" << obj.name << endl;
}
void Admin::ManagerDetails(Manager &obj)
{
    cout << "Manager :" << obj.name << endl;        
}
 
int main()
{
    Employee e;
    Manager m;
    Admin a;
    a.EmployeeDetails(e);
    a.ManagerDetails(m);
    return 0;
}