java.util.TreeSet的tailSet操作的时间复杂度是多少？

Question

I was implementing the 2D closest pair algorithm using sweepline, and it says that you need to find the six points above a certain y coordinate. What I did is I put the points in a TreeSet sorted by y-coordinate, and used the tailSet method to get all points above a certain point, and iterate up to 6 times.

I was wondering if the complexity of the tailSet operation is O(log n), and if it is, is iterating over the tailSet at most six times also O(log n)?

Reference: http://people.scs.carleton.ca/~michiel/lecturenotes/ALGGEOM/sweepclosestpair.pdf

Answer 1

AFAIK将tailSet设为O（log n），但对最后m元素进行迭代则为O(m * log n)

Answer 2

Hmm... It's strange to me. I thought that in terms of big O a process of creating a tailSet inside java.util.TreeSet is O(1).

Small clarification: tailSet(), headSet() and subSet() return very small objects that delegate all the hard work to methods of the underlying set. No new set is constructed. Hence O(1) and pretty insignificant.

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