需要数字的正则表达式，后跟字母，空格，破折号，斜杠等

Question

I'm just not that good at regex and I haven't been able to find an example of something close to what I need. Thanks in advance for your help. This is for a search entry box that will take the user directly to what they are looking for if they already know it's number or number+letter sequence

It has to start with a number and the number can be 1 to many digits, the letters following the numbers can be 0, 1, or 2 digits.

Examples of passing: 1 12 123456 123a 1234ab 123456789ab

Examples of failing: a ab a1 ab12 1abc 123abc 1-a 1_a

you get the point. For the passing strings, I also need to separate the numbers from the letters.

Thanks again.

Language is c#. I need to test the incoming string and then split it into it's number and letter parts if it passes the regex.

Answer 1

try

[0-9]+[a-z]{0,2}

Hope this helps.

Answer 2

Try this

var regex=new Regex("^(?<numbers>[0-9]+)(?<letters>[a-z]{0,2})$",RegexOptions.IgnoreCase);
var match=regex.Match(testString);

The property match.Success tells you if it succeed and the values can be obtained

var numbers=match.groups["numbers"].Value;

var letters=match.groups["letters"].Value;

Answer 3

This should work:

/([0-9]+)([a-z]{0,2})/

Depending upon what language you're using this regex in, the method for getting the full pattern match and subsequent subpattern matches may vary.

EDIT:

Revised second subpattern to match no letters, or a maximum of 2 letters.

Answer 4

/([0-9]+)([a-zA-Z]{0,2})/大写...

Answer 5

All the answers given still match the 1-a in the failing list, so here's my addition:

\b([0-9]+)([a-z]{0,2})(?!-)\b

Tested with: 1 12 123456 123a 1234ab 123456789ab a ab a1 ab12 1abc 123abc 1-a 1_a

Matches: 1 12 123456 123a 1234ab 123456789ab