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复制boost :: array <char> 到std :: string

[英]Copying boost::array<char> to std::string

I am trying to cvopy boost::array<char> to std::string . 我正在尝试将boost::array<char>std::string

boost::array<char, 1024> _buffer;
std::string data;
std::copy(_buffer.begin(), _buffer.begin()+bytes_transferred, data.begin());

which is not working. 这是行不通的。 So I changed it a little bit. 所以我做了一点修改。

char _buffer[1024];
std::string data;
std::copy(_buffer, _buffer+bytes_transferred, data.begin());

second one is not working either. 第二个也不工作。

The issue here is that copy assumes that space already exists for the data you're writing; 这里的问题是, copy假定您正在写入的数据已经存在空间; it doesn't create any new room for you. 它不会为您创建任何新房间。 Consequently, both of the above pieces of code cause undefined behavior, since you're going to be copying characters to a location where space hasn't previously been reserved. 因此,上述两段代码都会导致未定义的行为,因为您要将字符复制到以前未保留空间的位置。

The best way to do this would be to use the string constructor: 最好的方法是使用string构造函数:

boost::array<char, 1024> _buffer;
std::string data(_buffer.begin(), _buffer.end());

or 要么

char _buffer[1024];
std::string data(_buffer, _buffer + 1024);

This will initialize the string as a copy of the data stored in the array. 这会将字符串初始化为存储在数组中的数据的副本。

Hope this helps! 希望这可以帮助!

You can use back_insert_iterator . 您可以使用back_insert_iterator Assigning to it will call push_back function of the underlying container so you don't need to worry with allocating space manually. 对其进行分配将调用基础容器的push_back函数,因此您无需担心手动分配空间。

std::copy(_buffer.begin(), _buffer.begin()+bytes_transferred, std::back_inserter(data));

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