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以下java程序中的stackoverflow错误

[英]stackoverflow error in following java program

public class testing {    
    testing t=new testing();                

    public static void main(String args[]){   
        testing t1=new testing();  
        t1.fun();  
    }

    void fun(){         
        int a=2;        
        int b=t.fun2(a);  
        System.out.println(a+" "+b);  
    }

    int fun2(int a)  
    {
        a=3;  
        return a;  
    }  
}

why does above code giving following error? 为什么上面的代码会出现以下错误? I just want to know the reason because it is difficult to expect StackOverFlowError error in this case. 我只是想知道原因,因为在这种情况下很难期望StackOverFlowError错误。

Exception in thread "main" java.lang.StackOverflowError
at com.testing.<init>(testing.java:4)
at com.testing.<init>(testing.java:4)

You are recursively creating instance of testing 您以递归方式创建testing实例

public class testing {    
 testing t=new testing();        
//

}

While creating first instance it will create new Instance by testing t=new testing(); 在创建第一个实例时,它将通过testing t=new testing();来创建新的实例testing t=new testing(); which will again create new instance and so on 这将再次创建新实例等

try this solution, 试试这个解决方案

public class testing {                

    public static void main(String args[]){   
        testing t1=new testing();  
        t1.fun(t1);  
    }

    void fun(testing t1){         
        int a=2;        
        int b=t1.fun2(a);  
        System.out.println(a+" "+b);  
    }

    int fun2(int a)  
    {
        a=3;  
        return a;  
    }  
}

You have to create field at class level but instantiate it once where in main 您必须在类级别创建字段,但在main中将其实例化一次

public class Testing {    
    static Testing t1;              

    public static void main(String args[]){   
        t1=new Testing();  
        t1.fun();  
    }

    void fun(){         
        int a=2;        
        int b=t1.fun2(a);  
        System.out.println(a+" "+b);  
    }

    int fun2(int a)  
    {
        a=3;  
        return a;  
    }  
}

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