[英]transferring a javascript value to a php variable
将以下输出值转换为php变量的最佳方法是什么?
$(document).getUrlParam("id");
Through an ajax post. 通过ajax帖子。
$.ajax({
type: 'POST',
url: url,
data: data,
success: success,
dataType: dataType
});
You should use JSON format to send and receive data from javascript to PHP. 您应该使用JSON格式从javascript发送和接收数据到PHP。 For example
例如
function sendData(){
//with jquery, you can use `.post()`, `.get()` or for more control `.ajax()`
$.post(
//URL to send the data
url,
//data being sent, transformed to JSON
{dataSent: JSON.stringify(clientSideData)},
//Do something after sendind the data to server
function(dataReceived){
//transform data from json format to javascript object
var dataLog = jQuery.parseJSON(dataReceived);
//Do stuff
}
)
}
PHP: PHP:
//Receive data from POST
var phpVar = json_decode($_POST['dataSent'])
//send data back to javascript
echo json_encode(phpVar)
While all of these answers will get the value from javascript into the PHP script, I'd wonder if you need javascript at all. 虽然所有这些答案都会从javascript中获取PHP脚本的价值,但我想知道你是否需要javascript。
From what I can see from a brief google the getUrlParam plugin is useful for getting and then breaking down the URL. 从我在简短的谷歌中可以看到,getUrlParam插件对于获取然后分解URL非常有用。 Have you had a look at the variables available through $_SERVER ?
您是否看过$ _SERVER提供的变量? I'm sure you'd be able to find something suitable in there.
我相信你能找到合适的东西。
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