从当前目录的父目录的另一个子目录导入另一个模块（python）

Question

I'm attempting to write a game. I therefore have lots of different types of code and want to arrange them in a useful hierarchy.

I've looked at solutions that involve placing __init__.py in each folder but I'm still somewhat confused, though not as much as the python interpreter.

Now suppose resource1.py wants to import a function from physics1.py , or indeed any other .py file in the Game directory, how would I go about doing so?

I've tried from bin.physics.physics1 import function but obviously that doesn't work.

Thanks for your help.

/Game
    launcher.py
    /bin
        game.py
        __init__.py
        /physics
            __init__.py
            physics1.py
            physics2.py
    /resources
        __init__.py
        resource1.py

Answer 1

It is not possible with the normal import mechanism unless you make Game a package (ie, by putting an __init__.py inside the Game directory). The python relative import system only works within packages . It is not a general system for referring to arbitrary modules by their location in the directory structure. If you make Game a package, then you could do from ..bin.physics.physics1 import function .

Edit: Note also that relative imports don't work from a script executed as the main program. If you try to run resource.py directly and it uses relative imports, you'll get a "relative import attempted in non-package" error. It will work if you import resource from another module. This is because the relative import system is based on the "name" of the executing module, and when you run a script directly its name is __main__ instead of whatever it would usually be named. It's possible to get around this using the __package__ keyword if you really need to, but it can be a bit tricky.