如何制作example.com/eat load example.com/eat.php？

Question

I know that it is trying to load the .html version, i am pretty sure at least. I also think that it is something in an .htaccess file. I have tried a few different things from searching google and come up short. Basically i want it to work so that if there is no .html file by the name entered, it will go to the php one.

Is this possible?

Answer 1

Try this:

RewriteEngine On

RewriteCond %{REQUEST_FILENAME} !-s
RewriteCond %{REQUEST_FILENAME} !-l
RewriteCond %{REQUEST_FILENAME} !-d
RewriteCond %{REQUEST_FILENAME}.php -s
RewriteRule ^.*$ %{REQUEST_URI}.php [L,QSA]

The above rules say, if the requested file is of 0 size, or does not exist as a file, symbolic link, or directory and a file of the same name with a .php extension exists, then rewrite to the .php file.

This effectively rewrites site.com/foo to site.com/foo.php where foo can be anything.

I'm not quite clear on what you want. If you want to map non-existant .html files to a .php extension, try this instead:

RewriteEngine On

RewriteCond %{REQUEST_FILENAME} !-s
RewriteCond %{REQUEST_FILENAME} !-l
RewriteCond %{REQUEST_FILENAME} !-d
RewriteRule ^(.*)\.html$ $1.php [L,QSA]

This just says if the requested file does not exist and ends in .html , then grab the file name (less the .html ) and try to rewrite to the .php extension.

Answer 2

In htaccess

RewriteEngine on 
RewriteRule ^eat$ eat.php [L]  

Answer 3

Use MultiViews

Add this to apache configuration (either in httpd.conf , VirtualHost config, or in .htaccess ):

Options +MultiViews

Using rewriting for this is an overkill, when content-negotiation can do the job.