简体   繁体   English

比较两个数组

[英]Compare two arrays

I have two arrays: 我有两个数组:

array1=[1,2,3,4,5,6,7,8,9,10,11]
array2=[1,2]

I want to compare weather elements in "array2" is present in "array1" or not. 我想比较“ array1”中是否存在“ array2”中的天气元素。 If yes then I need to run a function, otherwise exit. 如果是,那么我需要运行一个函数,否则退出。 How to do it? 怎么做?

I have get the common items like this:- 我有这样的共同点:

NSMutableSet *idSet=[NSMutableSet setWithArray:Array1];
[idSet intersectSet:[NSSet setWithArray:Array2]];
NSArray *Common_array=[idSet allObjects];

in common array you can get the same object that are present in both array and is 0 object in Common_array than in both array there is none on object that are same. 在公共数组中,您可以获得两个数组中都存在的相同对象,并且Common_array中的对象为0,而在两个数组中都没有相同的对象。

An easy logic way to do this would be a for loop: 一种简单的逻辑方法是for循环:

for(int a = 0; a < array1.count; a++) {
    for(int b = 0; b < array2.count; b++) {
        if([[array1 objectAtIndex:a] isEqualToString:[array2 objectAtIndex:b]]) {
            //do something here
        }
    }
}

What about enumerating over array1? 枚举array1怎么样?

Something along the lines of 遵循以下原则

NSArray *array1 = ...;
NSArray *array2 = ...;

[array1 enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
    if ([array2 containsObject: obj]) {
        // Run the function you wanted to
    }
}];

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM