我如何使我的程序进入python中的下一个elif

Question

import random
print"hello what is your name?"
name = raw_input()
print"hello", name
print"wanna play a game? y, n"
choice = raw_input()
if choice =='y':
    print'good lets start a number guessing game'

elif choice =='n':
    print'maybe next time'
    exit()

random.randint(1,10)
number = random.randint(1,10)
print'pick a number between 1-10'
numberofguesses = 0
guess = input()

while numberofguesses < 10:
 if guess < number:
    print"too low"
 elif guess > number:
        print"too high"
 elif guess == number:
        print'your correct the number is', number
 break
if guess == number:
    print'CONGRATS YOU WIN THE GAME'

when i enter my guess into the program it only gives me one output for example i enter 8 programs output is "too high" but when i guess again the output is blank, how do i fix this? hello what is your name?

 ed
    hello ed
    wanna play a game? y, n
    y
    good lets start a number guessing game
    pick a number between 1-10
    2
    too low
    >>> 5
    5
    >>> 3
    3
    >>> 2
    2
    >>> 

Answer 1

I think this is what you want:

numberofguesses = 0

while numberofguesses < 10:
 guess = input()  #int(raw_input("Pick a number between 1 and 10: ")) would be much better here.
 numberofguesses+=1
 if guess < number:
    print "too low"
 elif guess > number:
    print "too high"
 elif guess == number:
    print 'your correct the number is', number
    break

With your version of the code, you guess once. If you're wrong, your program tries the same guess over and over again forever (assuming your break was actually supposed to be indented in the elif ). You might be typing new guesses into the terminal, but your program never sees them. If the break was actually in the correct place in your code, then you guess once and whether write or wrong it exits the loop right away.

Answer 2

your break is outside of your ifstatement

It will execute while loop one time and break no matter what