我如何使我的程序進入python中的下一個elif

Question

import random
print"hello what is your name?"
name = raw_input()
print"hello", name
print"wanna play a game? y, n"
choice = raw_input()
if choice =='y':
    print'good lets start a number guessing game'

elif choice =='n':
    print'maybe next time'
    exit()

random.randint(1,10)
number = random.randint(1,10)
print'pick a number between 1-10'
numberofguesses = 0
guess = input()

while numberofguesses < 10:
 if guess < number:
    print"too low"
 elif guess > number:
        print"too high"
 elif guess == number:
        print'your correct the number is', number
 break
if guess == number:
    print'CONGRATS YOU WIN THE GAME'

當我在程序中輸入我的猜測時，例如，我只能輸入一個輸出，例如，我輸入8個程序輸出為“太高”，但是當我再次猜測輸出為空白時，如何解決此問題？ 你好，你叫什么名字？

 ed
    hello ed
    wanna play a game? y, n
    y
    good lets start a number guessing game
    pick a number between 1-10
    2
    too low
    >>> 5
    5
    >>> 3
    3
    >>> 2
    2
    >>> 

Answer 1

我認為這是您想要的：

numberofguesses = 0

while numberofguesses < 10:
 guess = input()  #int(raw_input("Pick a number between 1 and 10: ")) would be much better here.
 numberofguesses+=1
 if guess < number:
    print "too low"
 elif guess > number:
    print "too high"
 elif guess == number:
    print 'your correct the number is', number
    break

使用您的代碼版本，您只需猜測一次。 如果您錯了，您的程序將一遍又一遍地嘗試相同的猜測（假設您的break實際上應該在elif縮進）。 您可能正在終端中輸入新的猜測，但是您的程序永遠看不到它們。 如果該break實際上在代碼中的正確位置，那么您只需猜測一次，無論是寫入還是錯誤，它都會立即退出循環。

Answer 2

您的休息不在您的ifstatement中

它會在while循環中執行一次，無論發生什么都會中斷