简体繁体 English

从InputStream创建Java 7 zip文件系统

[英]Create a Java 7 zip FileSystem from an InputStream

原文 2012-08-05 18:11:45 3 2 java/ zip/ java-7

Java 7 introduced a zip FileSystem. Java 7引入了一个zip FileSystem。 The link below illustrates how to create a zip FileSystem from a zip file. 以下链接说明了如何从zip文件创建zip文件系统。

http://docs.oracle.com/javase/7/docs/technotes/guides/io/fsp/zipfilesystemprovider.html http://docs.oracle.com/javase/7/docs/technotes/guides/io/fsp/zipfilesystemprovider.html

However, I can find no example of how to create a zip FileSystem from an InputStream. 但是，我找不到如何从InputStream创建zip FileSystem的示例。 Is that possible? 那可能吗？ If so, how? 如果是这样，怎么办？

Note: I know I can write the InputStream to disk and create a zip FileSystem as described. 注意：我知道我可以将InputStream写入磁盘并按说明创建一个zip FileSystem。 I consider that a hack, and I would prefer to avoid it. 我认为这是一种骇客，我希望避免这种情况。

2 个解决方案

No, it's not possible because the file system requires random access to the ZIP file. 否，这是不可能的，因为文件系统需要对ZIP文件的随机访问。

Shameless self-plug: You may find TrueZIP easier to work with and more powerful. 无耻的自我插拔：您可能会发现TrueZIP更易于使用且功能更强大。 However, the same constraint applies to it, too. 但是，同样的约束也适用于它。

Only a partial answer, but I expect you'll need a custom file system provider and this question about an in-memory file system might help . 只有部分答案，但是我希望您需要一个自定义文件系统提供程序，有关内存中文件系统的这个问题可能会有所帮助。 Note that the newFileSystem documentation shows a memory://... URL scheme, but no more detail. 请注意， newFileSystem文档显示了一个memory://... URL方案，但没有更多细节。

As pointed out in another answer, the file system requires bidirectional access to the data, so this assumes enough memory to load it entirely. 正如另一个答案中指出的那样，文件系统要求对数据进行双向访问，因此这假定有足够的内存来完全加载它。