[英]SQL Multiple condition on single field
Hi Can someone help me about sql 嗨,有人可以帮助我关于SQL
i have this data in my Table: 我在表格中有这些数据:
date_added | location | status 2012-08-01 Manila 1 2012-08-01 Japan 1 2012-08-01 Cebu 1 2012-08-04 Manila 1 2012-08-04 Cebu 1 2012-08-04 Africa 1 2012-08-06 Manila 1 2012-08-06 Japan 1 2012-08-06 Cebu 1
how can i get the date_added result with the location in 'Manila' , 'Japan', 'Cebu' and has status =1 如何在“马尼拉”,“日本”,“宿雾”中获取date_added结果并且状态= 1
The three data must exist before i can get the date. 在我得到日期之前,这三个数据必须存在。
Result should be: based on this table 结果应该是:基于此表
date_added 2012-08-01 2012-08-06
since on 2012-08-04 'Japan' did not exists. 因为在2012-08-04'日本'不存在。
My Current SAMPLE SQL: 我当前的SAMPLE SQL:
SELECT date_added FROM TABLE WHERE location ='Manila' AND location ='Japan' AND location ='Cebu' AND STATUS =1;
Please help.....any help will greatly appreciated 请帮助.....任何帮助将不胜感激
try this: 试试这个:
SELECT DATE_ADDED
FROM TABLE
WHERE LOCATION IN ('MANILA' , 'JAPAN' , 'CEBU')
AND STATUS =1
GROUP BY DATE_ADDED
HAVING (COUNT(DISTINCT LOCATION)=3)
You need the SQL IN
operator: 您需要SQL
IN
运算符:
SELECT date_added FROM TABLE WHERE location IN ('Manila', 'Japan', 'Cebu') AND STATUS =1;
Or alternatively, you need to use the OR
operator and bracket the location statements: 或者,您需要使用
OR
运算符并括住location语句:
SELECT date_added FROM TABLE WHERE ( location ='Manila' OR location ='Japan' OR location ='Cebu' ) AND STATUS =1;
Try this 试试这个
SELECT date_added FROM TABLE WHERE location ='Manila' or location ='Japan' or location ='Cebu' AND STATUS =1;
or 要么
select date_added FROM TABLE WHERE location in ('Manila','Japan','Cebu') AND status='1' GROUPED BY date_added
WHERE location IN ('Manila' , 'Japan', 'Cebu') AND status = 1
when you use AND
condition on the same field,it will always result to false because a field can only have 1 possible value
. 当你在同一个字段上使用
AND
条件时,它总是会导致错误,因为一个字段只能有1 possible value
。 So you needto use IN
for that 所以你需要使用
IN
SELECT Date_added
FROM myTable
WHERE `Location` IN ('MANILA' , 'JAPAN' , 'CEBU')
AND `Status` =1
GROUP BY Date_added
HAVING COUNT(DISTINCT Location) = 3
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