SQL单个字段的多个条件

Question

嗨，有人可以帮助我关于SQL

我在表格中有这些数据：

date_added | location     |  status
2012-08-01    Manila           1
2012-08-01    Japan            1
2012-08-01    Cebu             1

2012-08-04    Manila           1
2012-08-04    Cebu             1
2012-08-04    Africa           1

2012-08-06    Manila           1
2012-08-06    Japan            1
2012-08-06    Cebu             1

如何在“马尼拉”，“日本”，“宿雾”中获取date_added结果并且状态= 1

在我得到日期之前，这三个数据必须存在。

结果应该是：基于此表

date_added 
 2012-08-01
 2012-08-06

因为在2012-08-04'日本'不存在。

我当前的SAMPLE SQL：

SELECT date_added FROM TABLE WHERE location ='Manila' AND location ='Japan' 
       AND location ='Cebu' AND STATUS =1;

请帮助.....任何帮助将不胜感激

Answer 1

试试这个：

SELECT DATE_ADDED 
FROM TABLE 
WHERE LOCATION IN ('MANILA' , 'JAPAN' , 'CEBU')
AND STATUS =1
GROUP BY DATE_ADDED
HAVING (COUNT(DISTINCT LOCATION)=3)

Answer 2

您需要SQL IN运算符：

SELECT date_added FROM TABLE WHERE location IN ('Manila', 'Japan', 'Cebu') AND STATUS =1;

或者，您需要使用OR运算符并括住location语句：

SELECT date_added FROM TABLE WHERE ( location ='Manila' OR location ='Japan' OR location ='Cebu' ) AND STATUS =1;

Answer 3

试试这个

SELECT date_added FROM TABLE WHERE location ='Manila' or location ='Japan'  or location ='Cebu' AND STATUS =1;

要么

select date_added FROM TABLE WHERE location in ('Manila','Japan','Cebu') AND status='1' GROUPED BY date_added

Answer 4

WHERE location IN ('Manila' , 'Japan', 'Cebu') AND status = 1

Answer 5

当你在同一个字段上使用AND条件时，它总是会导致错误，因为一个字段只能有1 possible value 。 所以你需要使用IN

SELECT Date_added 
FROM   myTable
WHERE  `Location` IN ('MANILA' , 'JAPAN' , 'CEBU')
          AND `Status` =1
GROUP BY Date_added 
HAVING   COUNT(DISTINCT Location) = 3