[英]Python regex for matching two or three white spaces
I'm trying to match the following text with a regex in Python 2.7 我试图将以下文本与Python 2.7中的正则表达式相匹配
SUBCASE 8
SUBCASE 9
SUBCASE 10
SUBCASE 11
The number of spaces between "subcase" and the number drops from 3 to 2. I'm trying to use this regex in Python: “subcase”和数字之间的空格数从3下降到2.我试图在Python中使用这个正则表达式:
(SUBCASE)[\\s+]([0-9]+)
Where am I going wrong? 我哪里错了? Shouldn't the
\\s+
mean "catch any white spaces more than one"? 不应该
\\s+
意味着“抓住任何一个以上的空白区域”吗?
You'll want: 你想要:
SUBCASE\s+([0-9]+)
or 要么
SUBCASE\s+(\d+)
Putting \\s+
inside of [...]
means, that you want precisely one symbol that either is a whitespace character, or a plus. 将
\\s+
放在[...]
意味着,您只需要一个符号,即空白字符或加号。
(SUBCASE)\s+([0-9]+)
你使用了[\\ s +]来做一个空格或+符号的字符匹配
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