用“\\n”替换“\\r\\n”

Question

I have some text data that is printing out the actual characters "\\r\\n" (so four characters total). I'd like to replace those four characters with the single "\\n" character, but I can't seem to make Python do it for me. I'm currently trying:

mytext.replace("\r\n", "\n")

But that just prints out "\\n" (two characters, not one). I feel like I'm probably missing something obvious, but any help would be appreciated.

Answer 1

我建议使用分割线而不是正则表达式或搜索/替换

"\n".join(mytext.splitlines())

Answer 2

mytext.replace(r"\r\n", r"\n")

'r' 表示一个原始字符串，它告诉 python 将文本中的反斜杠解释为文字字符而不是转义字符。

Answer 3

"\\n".join(mytext.splitlines()) This works for me. mytext.replace(r"\\r\\n", r"\\n") , this not work.

Answer 4

This is a solution to try if any of the above did not work (which was the case for me using the Anaconda Distribution of Python3).

mytext.replace("\\r\\n", "\\n")

This has to do with \\ being used as an escape character. I thought that the above answers that used the raw string formatter would achieve the same thing, but for whatever reason that did not work for me, and this did.

Answer 5

Sorry, I misread your question:

In that case, you should prefix your string with ar to use raw strings:

mytext.replace(r"\r\n", r"\n")

Answer 6

python will auto convert '\\r\\n' to '\\n' when you read file to variable, and vice versa. But if you write back to file with "binary mode", then python will write exactly your content to file. so simply read file to variable and write back with binary mode will auto convert '\\r\\n' to '\\n' in windows platform.

file_name = 'test.sh'
file_content = ''
with open(file_name) as f:
    file_content = f.read()

with open(file_name, 'wb') as f:
    f.write(file_content)

Answer 7

LINEBREAK = "\n"

with open(filename) as f:
    s = f.read()
    s = LINEBREAK.join(s.splitlines())
with open(new_filename, "wb") as f:
    f.write(s + "\n")

If you want to use '\\r\\n' as linebreak, just change the LINEBREAK .