使用javascript获取存在某个CSS属性的所有元素？

Question

Is there a way to get all elements on the DOM with the presence of a certain CSS property? Say I wanted to get all elements with a background-image CSS value -- how could I select all of them? I preferably want to avoid using Jquery.

Answer 1

To be absolutely sure, you have get the style like this:

var elms = document.all ? document.all : document.body.getElementsByTagName("*");
for (i = 0; i < elms.length; i++) {
    if ((elms[i].currentStyle && elms[i].currentStyle.backgroundImage.length > 0) ||
    (window.getComputedStyle &&
    window.getComputedStyle(elms[i]).getPropertyValue("background-image"))) {
        alert('found one!');
    } 
}​

CurrentStyle is for IE, getComputedStyle is for the rest.

Answer 2

on a modern browser you can use getComputedStyles

var elements = document.getElementsByTagName("*");
var haveBg = new Array();
for (i = 0; i < elements.length; i++) {
    var style = window.getComputedStyle(elements[i], null);
    if (style.getPropertyValue("background-image") != 'none') {
        haveBg.push(elements[i]);
    } 
}

Answer 3

var elms = document.all ? document.all : document.getElementsByTagName("*");
for (i = 0; i < elms.length; i++) {
   if (elms[i].style.backgroundImage.length > 0) {
        alert('found one!');
    } 
}

It would be better to use the exact tag name rather then '*' if you know what it would be before hand