python的列表方法`index（）`是否可以在列表中找到列表元素

Question

update 0

My test code was very naive and I have to enhance it as follows ...

n=2
times=intervals([9,30],[11,30])
u=[]
v=[]

for t in times:
    u+= [[t[0],t[1]]]
    for i in range(0,n):
       t.append("")
    t[3]=3
    v+=[t]
    print "t:",t

print "v:",v

print "u.index:",u.index([10, 30])

... so from my test code I need to use the value of variable v for variable times and I need to use the result of u.index([10, 30]) for my index. BrenBarn finally got through to me, I hope.

My test code that follows ...

n=2
times=intervals([9,30],[11,30])
for t in times:
    for i in range(0,n):
       t.append("")
    t[3]=3
    print t

... produces the following print result

[9, 30, '09:30AM', 3, '']
[10, 0, '10:00AM', 3, '']
[10, 30, '10:30AM', 3, '']
[11, 0, '11:00AM', 3, '']

Can the index() method be used to find, for example, the index in list t of the "element" [10, 30, ... ]? Or do I need to construct the integer list [930,100,1030,110] and index() that list, instead? Or are there other suggestions?

Answer 1

Did you even try it, or am I misunderstanding your question?

>>> t = [[9, 30, '09:30AM', 3, ''],
... [10, 0, '10:00AM', 3, ''],
... [10, 30, '10:30AM', 3, ''],
... [11, 0, '11:00AM', 3, '']]
>>> t.index([10, 30, '10:30AM', 3, ''])
2