如何将linux命令的输出复制到C ++变量

Question

I'm calling a LINUX command from within a C++ programme which creates the following output. I need to copy the first column of the output to a C++ variable (say a long int). How can I do it?? If that is not possible how can I copy this result into a .txt file with which I can work with?

Edit

          0 +0
 2361294848 +2361294848
 2411626496 +50331648
 2545844224 +134217728
 2713616384 +167772160

I have this stored as a file, file.txt and I'm using the following code to extract the left column with out the 0 to store it at integers

string stringy="";
int can_can=0;
for(i=begin;i<length;i++)
{
if (buffer[i]==' ' && can_can ==1) //**buffer** is the whole text file read in char*
{
num=atoi(stringy.c_str());
array[univ]=num; // This where I store the values.
univ+=1;
can_can=1;
  }
  else if (buffer[i]==' ' && can_can ==0) 
 {
stringy="";  
}
else if (buffer[i]=='+')
{can_can=0;}
else{stringy.append(buffer[i]);}
}

I'm getting a segmentation error for this. What can be done ?

Thanks in advance.

Answer 1

Just create a simple streambuf wrapper around popen()

#include <iostream>
#include <stdio.h>

struct SimpleBuffer: public std::streambuf
{   
    typedef std::streambuf::traits_type traits;
    typedef traits::int_type            int_type;

    SimpleBuffer(std::string const& command)
        : stream(popen(command.c_str(), "r"))
    {   
        this->setg(&c[0], &c[0], &c[0]);
        this->setp(0, 0); 
    }   
    ~SimpleBuffer()
    {   
        if (stream != NULL)
        {   
            fclose(stream);
        }   
    }   
    virtual int_type underflow()
    {   
        std::size_t size = fread(c, 1, 100, stream);
        this->setg(&c[0], &c[0], &c[size]);

        return size == 0 ? EOF : *c; 
    }   

    private:
        FILE*   stream;
        char    c[100];

};  

Usage:

int main()
{
    SimpleBuffer    buffer("echo 55 hi there Loki");
    std::istream    command(&buffer);

    int  value;
    command >> value;

    std::string line;
    std::getline(command, line);

    std::cout << "Got int(" << value << ") String (" << line << ")\n";
}

Result:

> ./a.out
Got int(55) String ( hi there Loki)

Answer 2

It is popen you're probably looking for. Try

man popen

.

Or see this little example:

#include <iostream>
#include <stdio.h>

using namespace std;

int main() 
{

    FILE *in;
    char buff[512];

    if(!(in = popen("my_script_from_command_line", "r"))){
        return 1;
    }

    while(fgets(buff, sizeof(buff), in)!=NULL){
          cout << buff; // here you have each line 
                        // of the output of your script in buff
    }
    pclose(in);

    return 0;
}

Answer 3

You probably want to use popen to execute the command. This will give you a FILE * that you can read its output from. From there, you can parse out the first number with (for example) something like:

fscanf(inpipe, "%d %*d", &first_num);

which, just like when reading from a file, you'll normally repeat until you receive an end of file indication, such as:

long total = 0;

while (1 == fscanf(inpipe, "%l %*d", &first_num))
    total = first_num;

printf("%l\n", total);

Answer 4

Unfortunately, it's not easy since the platform API is written for C. The following is a simple working example:

#include <cstdio>
#include <iostream>

int main() {
    char const* command = "ls -l";

    FILE* fpipe = popen(command, "r");

    if (not fpipe) {
        std::cerr << "Unable to execute commmand\n";
        return EXIT_FAILURE;
    }

    char buffer[256];
    while (std::fgets(buffer, sizeof buffer, fpipe)) {
        std::cout << buffer;
    }

    pclose(fpipe);
}

However, I'd suggest wrapping the FILE* handle in a RAII class to take care of resource management.