如何将列表中的项目连接到单个字符串？

Question

如何将字符串列表连接成单个字符串？

['this', 'is', 'a', 'sentence']    →    'this-is-a-sentence'

Answer 1

Use str.join :

>>> sentence = ['this', 'is', 'a', 'sentence']
>>> '-'.join(sentence)
'this-is-a-sentence'
>>> ' '.join(sentence)
'this is a sentence'

Answer 2

A more generic way to convert python lists to strings would be:

>>> xs = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>> ''.join(map(str, xs))
'12345678910'

Answer 3

It's very useful for beginners to know why join is a string method .

It's very strange at the beginning, but very useful after this.

The result of join is always a string, but the object to be joined can be of many types (generators, list, tuples, etc).

.join is faster because it allocates memory only once. Better than classical concatenation (see, extended explanation ).

Once you learn it, it's very comfortable and you can do tricks like this to add parentheses.

>>> ",".join("12345").join(("(",")"))
Out:
'(1,2,3,4,5)'

>>> list = ["(",")"]
>>> ",".join("12345").join(list)
Out:
'(1,2,3,4,5)'

Answer 4

Edit from the future : Please don't use the answer below. This function was removed in Python 3 and Python 2 is dead. Even if you are still using Python 2 you should write Python 3 ready code to make the inevitable upgrade easier.

---

Although @Burhan Khalid's answer is good, I think it's more understandable like this:

from str import join

sentence = ['this','is','a','sentence']

join(sentence, "-") 

The second argument to join() is optional and defaults to " ".

Answer 5

list_abc = ['aaa', 'bbb', 'ccc']

string = ''.join(list_abc)
print(string)
>>> aaabbbccc

string = ','.join(list_abc)
print(string)
>>> aaa,bbb,ccc

string = '-'.join(list_abc)
print(string)
>>> aaa-bbb-ccc

string = '\n'.join(list_abc)
print(string)
>>> aaa
>>> bbb
>>> ccc

Answer 6

We can also use Python's reduce function:

from functools import reduce

sentence = ['this','is','a','sentence']
out_str = str(reduce(lambda x,y: x+"-"+y, sentence))
print(out_str)

Answer 7

We can specify how we have to join the string. Instead of '-', we can use ' '

sentence = ['this','is','a','sentence']
s=(" ".join(sentence))
print(s)

Answer 8

If you want to generate a string of strings separated by commas in final result, you can use something like this:

sentence = ['this','is','a','sentence']
sentences_strings = "'" + "','".join(sentence) + "'"
print (sentences_strings) # you will get "'this','is','a','sentence'"

Answer 9

If you have mixed content list. And want to stringify it. Here is one way:

Consider this list:

>>> aa
[None, 10, 'hello']

Convert it to string:

>>> st = ', '.join(map(str, map(lambda x: f'"{x}"' if isinstance(x, str) else x, aa)))
>>> st = '[' + st + ']'
>>> st
'[None, 10, "hello"]'

If required, convert back to list:

>>> ast.literal_eval(st)
[None, 10, 'hello']

Answer 10

list = [1, "a", 3, "b", 3.14]

list_str = ""

for item in list:
  
    list_str += str(item)

print (list_str)

# > 1a3b3.14

Answer 11

def eggs(someParameter):
    del spam[3]
    someParameter.insert(3, ' and cats.')


spam = ['apples', 'bananas', 'tofu', 'cats']
eggs(spam)
spam =(','.join(spam))
print(spam)

Answer 12

Without .join() method you can use this method:

my_list=["this","is","a","sentence"]

concenated_string=""
for string in range(len(my_list)):
    if string == len(my_list)-1:
        concenated_string+=my_list[string]
    else:
        concenated_string+=f'{my_list[string]}-'
print([concenated_string])
    >>> ['this-is-a-sentence']

So, range based for loop in this example , when the python reach the last word of your list, it should'nt add "-" to your concenated_string. If its not last word of your string always append "-" string to your concenated_string variable.

Answer 13

This will help for sure -

arr=['a','b','h','i']     # let this be the list
s=""                      # creating a empty string
for i in arr:
   s+=i                   # to form string without using any function
print(s)