[英]Extract value using JSON Path from array
I have Json like this below 我在下面有Json
{"pd":"{\"e\":{\"h\":{\"ak\":\"120\",\"at\":\"app\"},\"b\":[{\"ts\":1319549658547,\"tz\":-400,\"s\":\"StartUpScreen\",\"et\":8,\"ev\":\"sessionStart\",\"si\":\"19477682-de55-414f-82c9-19bec331dc33\",\"tt\":{\"day\":\"Tuesday\"}},{\"ts\":132,\"tz\":-400,\"s\":\"StartUpScreen\",\"et\":3,\"ev\":\"AutomaticFeedRefresh\",\"si\":\"19477682-de55-414f-82c9-19bec331dc33\",\"tt\":{}},{\"ts\":131,\"tz\":-400,\"s\":\"MainScreen\",\"et\":3,\"ev\":\"MainScreen Event\",\"si\":\"19477682-de55-414f-82c9-19bec331dc33\",\"tt\":{}}],\"tt\":{\"OSV\":\"7.10\"}}}","serverPayload":{"httpHeaders":{"x-bluecoat-via":["35D3468EFF4D5F18"],"content-type":["application\/x-www-form-urlencoded"]},"senderIp":["101.100.000.100"]}}
I just need the values of ak
, b [ts,si and tt[day]]
and senderIp
. 我只需要
ak
, b [ts,si and tt[day]]
和senderIp
。 Now I have 2 questions, how do I extract all 'ts' attributes in 'b' and 'senderIp'. 现在我有2个问题,如何在'b'和'senderIp'中提取所有'ts'属性。 I have used the below code for ak, ts and si.
我已经使用下面的代码为ak,ts和si。 I am not sure how I get 'tt', also while I run this code I get an exception like below
我不知道如何得到'tt',同时我运行此代码时会得到如下的异常
String pd = JsonPath.read(jsonString, "$.pd");
String ak = JsonPath.read(pd, "$e.h.ak");
String ak = JsonPath.read(pd, "$e.h.b[0]");
// String b = JsonPath.read(pd,"$.e.b[0][0]");
// String b = JsonPath.read(pd,"$.e.b[0][5]");
System.out.println("value of ak: "+ak);
Exception in thread "main" java.lang.ClassCastException: net.minidev.json.JSONObject cannot be cast to java.lang.String
. 线程“main”中的异常
java.lang.ClassCastException: net.minidev.json.JSONObject cannot be cast to java.lang.String
。
$.ehb[0]
looks like a JavaScript object (with fields including "ts" and "tz"), not a string. $.ehb[0]
看起来像一个JavaScript对象(包含“ts”和“tz”的字段),而不是字符串。 So it's reasonable for your JSON parser to treat it as a JSONObject rather than a string. 因此,您的JSON解析器将其视为JSONObject而不是字符串是合理的。 Probably you need to drill down to
$.ehb[0].ts
or whatever field you're interested in. Something like this: 可能你需要深入到
$.ehb[0].ts
或你感兴趣的任何领域。这样的东西:
long ts = JsonPath.read(pd, "$e.h.b[0].ts");
I'm assuming it's your second String ak =
line which causes the exception. 我假设它是你的第二个
String ak =
line导致异常。 I'm having trouble understanding your other question about the "ts" attributes. 我无法理解你关于“ts”属性的其他问题。 Maybe you could format the JSON string for easier reading?
也许您可以格式化JSON字符串以便于阅读?
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