在C中初始化2d数组

Question

Here is my code:

int main() { 
    int x, y; 
    int *xptr, *yptr; 
    int array[10][10]; 
    int j; 
    int k; 
    int z = 0; 

    for(j = 0; j < 10; j++) { 
        for(k = 0; k < 10; k++) { 
            array[j][k] = j * 10 + k; 
        } 
    } 

    xptr = &array[0][0]; 

    for(j = 0; j < 10; j++) { 
        for(k = 0; k < 10; k++) { 
            printf("array[%d][%d] = %d \n", j, k, *(xptr + j), (xptr + k)); 
        } 
    } 

    system("PAUSE"); 
}

I am trying to initialize a 2d array so that at [0][0] it equals 0 and at [9][9] it equals 99. With the way that it is now, [0][0-9] all equal 0 and then [1][0-9] all equal 1. How would I properly load this array in the fashion that I mentioned?

Answer 1

for(j = 0; j < 10; j++) {
      for(k = 0; k < 10; k++) {
            array[j][k] = j*10 + k;
      }
}

Answer 2

I'm assuming you've actually declared everything, but didn't include it in the example. You simply want

array[j][k] = j*10 + k;