[英]Isolating columns with identical values
I am trying to isolate those columns of a dataframe for which all observations have the same value (ignoring NAs). 我试图隔离所有观察结果都具有相同值的数据框的那些列(忽略NA)。 See below for a hypothetical example: 参见下面的假设示例:
ForestName <- rep("Planige", 4)
TreeNumber <- c(1:4)
Height <- c(2.3, 2, 2.1, 2.9)
Type <- c("AA", "AA", NA, "AA")
df <- data.frame(ForestName, TreeNumber, Height, Type)
df
The new dataframe should contain ForestName and Type. 新数据框应包含ForestName和Type。 The columns with unequal values (TreeNumber and Height) should be contained in another dataframe. 具有不相等值(TreeNumber和Height)的列应包含在另一个数据框中。
You can use unique
and check if this reduces to a single element: 您可以使用unique
并检查它是否减少为单个元素:
df[sapply(df,function(x) length(unique(x[!is.na(x)])))==1]
ForestName Type
1 Planige AA
2 Planige AA
3 Planige <NA>
4 Planige AA
Or test that all
elements are equal to the first non- NA
: 或测试all
元素是否等于第一个非NA
:
df[sapply(df, function(x) all(x==na.omit(x)[1],na.rm=T))]
ForestName Type
1 Planige AA
2 Planige AA
3 Planige <NA>
4 Planige AA
Among many other ways, I'm sure: 在许多其他方式中,我确信:
df[,sapply(df,function(x) {length(unique(x[!is.na(x)])) > 1})]
TreeNumber Height
1 1 2.3
2 2 2.0
3 3 2.1
4 4 2.9
And you can negate the sapply
expression to get the other columns. 您可以取反sapply
表达式以获取其他列。
使用相同的基本原理的更紧凑的方法
Filter(function(x){length(unique(x[!is.na(x)])) <=1}, df)
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