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在 C# 中创建正弦波或方波

[英]Creating sine or square wave in C#

How do I generate an audio sine or square wave of a given frequency?如何生成给定频率的音频正弦波或方波?

I am hoping to do this to calibrate equipment, so how precise would these waves be?我希望这样做是为了校准设备,那么这些波的精确度如何?

You can use NAudio and create a derived WaveStream that outputs sine or square waves which you could output to the soundcard or write to a WAV file.您可以使用NAudio并创建一个派生的 WaveStream 来输出正弦波或方波,您可以将其输出到声卡或写入WAV文件。 If you used 32-bit floating point samples you could write the values directly out of the sin function without having to scale as it already goes between -1 and 1.如果您使用 32 位浮点样本,您可以直接从 sin 函数中写入值,而无需缩放,因为它已经在 -1 和 1 之间。

As for accuracy, do you mean exactly the right frequency, or exactly the right wave shape?至于准确性,您是指准确的频率,还是完全正确的波形? There is no such thing as a true square wave, and even the sine wave will likely have a few very quiet artifacts at other frequencies.没有真正的方波这样的东西,即使是正弦波,在其他频率下也可能会有一些非常安静的伪影。 If it's accuracy of frequency that matters, you are reliant on the stability and accuracy of the clock in your sound card.如果重要的是频率的准确性,则您依赖于声卡中时钟的稳定性和准确性。 Having said that, I would imagine that the accuracy would be good enough for most uses.话虽如此,我认为准确度对于大多数用途来说已经足够了。

Here's some example code that makes a 1 kHz sample at a 8 kHz sample rate and with 16 bit samples (that is, not floating point):下面是一些示例代码,它以 8 kHz 采样率和 16 位采样(即非浮点)生成 1 kHz 采样:

int sampleRate = 8000;
short[] buffer = new short[8000];
double amplitude = 0.25 * short.MaxValue;
double frequency = 1000;
for (int n = 0; n < buffer.Length; n++)
{
    buffer[n] = (short)(amplitude * Math.Sin((2 * Math.PI * n * frequency) / sampleRate));
}

This lets you give frequency, duration, and amplitude, and it is 100% .NET CLR code.这让你可以给出频率、持续时间和幅度,它是 100% .NET CLR 代码。 No external DLL's.没有外部DLL。 It works by creating a WAV-formatted MemoryStream which is like creating a file in memory only, without storing it to disk.它通过创建一个 WAV 格式的MemoryStream ,就像只在内存中创建一个文件,而不将它存储到磁盘。 Then it plays that MemoryStream with System.Media.SoundPlayer .然后它使用System.Media.SoundPlayer播放MemoryStream

using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Windows.Forms;

public static void PlayBeep(UInt16 frequency, int msDuration, UInt16 volume = 16383)
{
    var mStrm = new MemoryStream();
    BinaryWriter writer = new BinaryWriter(mStrm);

    const double TAU = 2 * Math.PI;
    int formatChunkSize = 16;
    int headerSize = 8;
    short formatType = 1;
    short tracks = 1;
    int samplesPerSecond = 44100;
    short bitsPerSample = 16;
    short frameSize = (short)(tracks * ((bitsPerSample + 7) / 8));
    int bytesPerSecond = samplesPerSecond * frameSize;
    int waveSize = 4;
    int samples = (int)((decimal)samplesPerSecond * msDuration / 1000);
    int dataChunkSize = samples * frameSize;
    int fileSize = waveSize + headerSize + formatChunkSize + headerSize + dataChunkSize;
    // var encoding = new System.Text.UTF8Encoding();
    writer.Write(0x46464952); // = encoding.GetBytes("RIFF")
    writer.Write(fileSize);
    writer.Write(0x45564157); // = encoding.GetBytes("WAVE")
    writer.Write(0x20746D66); // = encoding.GetBytes("fmt ")
    writer.Write(formatChunkSize);
    writer.Write(formatType);
    writer.Write(tracks);
    writer.Write(samplesPerSecond);
    writer.Write(bytesPerSecond);
    writer.Write(frameSize);
    writer.Write(bitsPerSample);
    writer.Write(0x61746164); // = encoding.GetBytes("data")
    writer.Write(dataChunkSize);
    {
        double theta = frequency * TAU / (double)samplesPerSecond;
        // 'volume' is UInt16 with range 0 thru Uint16.MaxValue ( = 65 535)
        // we need 'amp' to have the range of 0 thru Int16.MaxValue ( = 32 767)
        double amp = volume >> 2; // so we simply set amp = volume / 2
        for (int step = 0; step < samples; step++)
        {
            short s = (short)(amp * Math.Sin(theta * (double)step));
            writer.Write(s);
        }
    }

    mStrm.Seek(0, SeekOrigin.Begin);
    new System.Media.SoundPlayer(mStrm).Play();
    writer.Close();
    mStrm.Close();
} // public static void PlayBeep(UInt16 frequency, int msDuration, UInt16 volume = 16383)

Try from Creating sine and save to wave file in C#尝试在 C# 中创建正弦并保存到波形文件

private void TestSine()
{
    IntPtr format;
    byte[] data;
    GetSineWave(1000, 100, 44100, -1, out format, out data);
    WaveWriter ww = new WaveWriter(File.Create(@"d:\work\sine.wav"),
        AudioCompressionManager.FormatBytes(format));
    ww.WriteData(data);
    ww.Close();
}

private void GetSineWave(double freq, int durationMs, int sampleRate, short decibel, out IntPtr format, out byte[] data)
{
    short max = dB2Short(decibel);//short.MaxValue
    double fs = sampleRate; // sample freq
    int len = sampleRate * durationMs / 1000;
    short[] data16Bit = new short[len];
    for (int i = 0; i < len; i++)
    {
        double t = (double)i / fs; // current time
        data16Bit[i] = (short)(Math.Sin(2 * Math.PI * t * freq) * max);
    }
    IntPtr format1 = AudioCompressionManager.GetPcmFormat(1, 16, (int)fs);
    byte[] data1 = new byte[data16Bit.Length * 2];
    Buffer.BlockCopy(data16Bit, 0, data1, 0, data1.Length);
    format = format1;
    data = data1;
}

private static short dB2Short(double dB)
{
    double times = Math.Pow(10, dB / 10);
    return (short)(short.MaxValue * times);
}

Using Math.NET Numerics使用Math.NET 数字

https://numerics.mathdotnet.com/Generate.html https://numerics.mathdotnet.com/Generate.html

Sinusoidal正弦

Generates a Sine wave array of the given length.生成给定长度的正弦波阵列。 This is equivalent to applying a scaled trigonometric Sine function to a periodic sawtooth of amplitude 2π.这等效于将缩放三角正弦函数应用于幅度为 2π 的周期性锯齿波。

s(x)=A⋅sin(2πνx+θ) s(x)=A⋅sin(2πνx+θ)

Generate.Sinusoidal(length,samplingRate,frequency,amplitude,mean,phase,delay) Generate.Sinusoidal(length,samplingRate,frequency,amplitude,mean,phase,delay)

eg例如

 Generate.Sinusoidal(15, 1000.0, 100.0, 10.0);

returns array { 0, 5.9, 9.5, 9.5, 5.9, 0, -5.9, ... }返回数组 { 0, 5.9, 9.5, 9.5, 5.9, 0, -5.9, ... }

and there's also还有

Generate.Square(...

which will这将

create a periodic square wave...创建一个周期性方波...

can't speak about precision.不能谈精度。

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