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文件名,目录,文本,python文件夹子文件夹

[英]filenames, directory, text, python folders subfolders

With help from you i made a script that takes a list of subfolder (/desktop/filme/1,2,3,4,5...) from a folder (/desktop/filme/) and saves the name of each filenames of each subfolder (/desktop/filme/1/fileone, /desktop/filme/1/filetwo, /desktop/filme/1/filethree...) in another folder (/desktop/text/1.txt, /desktop/text/2.txt...). 在你的帮助下,我创建了一个脚本,从文件夹(/ desktop / filme /)中获取子文件夹(/ desktop / filme / 1,2,3,4,5 ...)的列表并保存每个文件名的名称每个子文件夹(/ desktop / filme / 1 / fileone,/ desktop / filme / 1 / filetwo,/ desktop / filme / 1 / filethree ...)在另一个文件夹中(/desktop/text/1.txt,/ desktop /文/ 2.txt ...)。 with the txt it work all right, i want it to save it in excel just like i save it in txt, for that i use xlwt. 使用txt它可以正常工作,我希望它将它保存在excel中就像我将其保存在txt中一样,因为我使用xlwt。 If you have any ideea for making it work with other libray i will try it. 如果你有任何想法让它与其他libray一起工作,我会尝试。

This is the script that saves txt-s: 这是保存txt-s的脚本:

import os
import os.path

for dirname, dirnames, filenames in os.walk(r"C:/Users/s/Desktop/filme/"):

    for subdirname in dirnames:

        foldere_filme = os.path.join(dirname, subdirname)
        numarul_folderelor = foldere_filme.replace("C:/Users/s/Desktop/filme/", "")
        print numarul_folderelor #1,2,3,4,5...
        root_text = "C:/Users/s/Desktop/text/"+numarul_folderelor+".txt"
        fisier_text = open(""+root_text+"", "w")
        for filenames in os.listdir(foldere_filme):
            numele_pt_text = filenames.replace(".avi", "")
            print numele_pt_text
            fisier_text.writelines(
                                "Full Movie: \n\n\nwatch "
                                +numele_pt_text+" online free, \nwatch "
                                +numele_pt_text+" online")
        fisier_text.close()

I want to adapt it for excel creation using xlwt or anything else: 我想使用xlwt或其他任何东西来适应excel创建:

import os
import xlwt
import os.path

for dirname, dirnames, filenames in os.walk(r"C:/Users/s/Desktop/filme/"):

    for subdirname in dirnames:
        foldere_filme = os.path.join(dirname, subdirname)
        numarul_folderelor = foldere_filme.replace("C:/Users/s/Desktop/filme/", "")
        print numarul_folderelor #1,2,3,4,5...
        wbk = xlwt.Workbook()
        sheet = wbk.add_sheet('sheet 1', cell_overwrite_ok=True)
        for filenames in os.listdir(foldere_filme):
            numele_pt_text = filenames.replace(".avi", "")
            print numele_pt_text
            sheet.write(0,0,numele_pt_text)
            sheet.write(1,0,numele_pt_text)
            sheet.write(2,0,numele_pt_text)
            sheet.write(3,0,numele_pt_text)
            sheet.write(4,0,numele_pt_text)
            sheet.write(5,0,numele_pt_text)
            sheet.write(6,0,numele_pt_text)
            sheet.write(7,0,numele_pt_text)
            sheet.write(8,0,numele_pt_text)
            sheet.write(9,0,numele_pt_text)
            wbk.save("C:/Users/s/Desktop/text/"+numarul_folderelor+".xls")

I'll work on it, but i would very much apriciate any help. 我会继续努力,但我会非常乐意帮助你。

But why do you open and close the text file for each line? 但是为什么要打开和关闭每行的文本文件? You could do something like this: 你可以这样做:

    numarul_folderelor = foldere_filme.replace("C:/Users/s/Desktop/filme/", "")
    print numarul_folderelor #1,2,3,4,5...

    root_text = "C:/Users/s/Desktop/text/"+numarul_folderelor+".txt"
    fisier_text = open(""+root_text+"", "w")

    for filenames in os.listdir(foldere_filme):
        numele_pt_text = filenames.replace(".avi", "")
        print numele_pt_text
        fisier_text.writelines(
                        "Full Movie: \n\n\nwatch "
                        +numele_pt_text+" online free, \nwatch "
                        +numele_pt_text+" online")
    fisier_text.close()

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