[英]SQL case sensitive string comparison with like and “=”
i have one table named category. 我有一个名为category的表。
in this table i have two columns 1.) cat_id
, 2.) cat_name
在这个表中我有两列1.)
cat_id
,2。) cat_name
in this table i have added record with this value : cat_id
= 1
, cat_name
= test
在此表中,我添加了具有此值的记录:
cat_id
= 1
, cat_name
= test
Now when i am going to run select query 现在,当我要运行选择查询时
SELECT * FROM category WHERE cat_name = 'Test'
this query returns me null result because in database record string is test
and in query it's a Test
mark the differance of capital string here. 此查询返回null结果,因为在数据库记录字符串中是
test
并且在查询中它是一个Test
标记这里的大写字符串的差异。 Instade of null result i want the result with 1st record. null结果的Instade我想要第一条记录的结果。
also i want same result in vice versa small and capital string. 我也想要相同的结果,反之亦然小和大写字符串。
i am using sqlite as database. 我使用sqlite作为数据库。
使用上部功能。
SELECT * FROM category WHERE upper(cat_name) = upper('Test')
SELECT * FROM category WHERE cat_name = 'Test' COLLATE NOCASE;
use LOWER: 使用LOWER:
SELECT * FROM category WHERE LOWER(cat_name) = 'test'
will get you all combinations of TeSt 将为您提供TeSt的所有组合
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