应用程序接受以下形式的命令行参数：*参数但不包含形式参数*或*参数*

Question

For example if my program name is test.c

Then for the following run command the argc = 2 instead of 4 .

$test abc pqr* *xyz*

Answer 1

Try to run:

$ echo abc pqr* *xyz*

and you will understand why you don't get the argc value you were expecting

Answer 2

It is probably because your shell / cmd.exe (no specifics are given!) use the * as file glob. If there are no files found that match the glob, the result will be empty.

Try calling you program like this:

test abc 'pqr*' 'xyz'

refer to http://en.wikipedia.org/wiki/Glob_%28programming%29 for details about globbing, and your shell's manual for details about escaping globs.