在C ++中取消分配多维数组

Question

How would I go about destroying a dynamic array of arbitrary size, dimensions, and type? Will delete[] automatically go down the levels of a two dimensional array or just delete the first level of pointers so the program need to manually iterate over each array level?

Ideally I need a single command (for use in a template class) that will destroy one to four dimensional arrays. It would also work if there is a way to check the number of dimensions of an array.

I am using dymanic arrays such as double* ar = new double[100];

Answer 1

如果您使用的是C ++，请使用std::vector和std::unique_ptr 。

Answer 2

You need to manually iterate over all levels to delete them.
If there is a way to check the dimensions, you can just use that to select the correct destruction process.

Also, why not use vectors ? they are fast and are automatically deallocated when out of scope

Answer 3

if you instanciate the 2 dimensional array like new int[10][20] the delete[] will destroy all the array, but if you created it iterating like myarray[i] = new int[20] so you will have to iterate again to destroy each dimension.

If you are not sure about how to destroy the array I would recoment you to use the STL vector.

Answer 4

Basically 1 new = 1 delete and 10 new = 10 delete , so you have to delete everything you allocate, the number of those operation called should be equal.

There's no way of knowing (from compilers/programs point of view) what's the real data pointer, what's just some trash or what is referenced elsewhere (and will be used) and so on.