通过sys.argv获取列表

Question

I pass mylist as an argument to be get after by sys.argv I do this:

mylist = str(list)
nbre = str(nbre)
comm = 'python2.6 file.py ' + mylist + ' ' + nbre + ' &'
os.system(comm)

In file.py , I am expected to get mylist by this way and which contains [machine1,machine2] but when doing:

mylist = sys.argv[1]

I get [machine1 , which is wrong. When I display sys.argv I found:

['file.py','[machine1,','machine2]','1']

I didn't understand why my list is composed like that?

Answer 1

Apart from this being a terrible way to communicate a list from one python script to another, you'd need to use quotes around the list to prevent it from being split by the shell:

comm = 'python2.6 file.py "%s" "%s" &' % (mylist, nbre)

I've used string formatting to put the quotes around mylist and nbre .

You really want to look into the subprocess module to invoke other processes without the shell getting in the way.