[英]How to find the difference between two dates in hours in R?
At the extreme risk of being modded down for asking "obvious" questions, how do I find the difference between two dates in hours in R? 由于被问到“明显”问题而被降低风险的极大风险,如何找到R中两个小时之间的差异?
> ISOdate(2004,1,6) - ISOdate(2004,1,1)
Time difference of 5 days
> as.POSIXlt(ISOdate(2004,1,6) - ISOdate(2004,1,1))
Error in as.POSIXlt.default(ISOdate(2004, 1, 6) - ISOdate(2004, 1, 1)) :
do not know how to convert 'ISOdate(2004, 1, 6) - ISOdate(2004, 1, 1)' to class "POSIXlt"
> (ISOdate(2004,1,6) - ISOdate(2004,1,1))$year
Error in (ISOdate(2004, 1, 6) - ISOdate(2004, 1, 1))$year :
$ operator is invalid for atomic vectors
> (ISOdate(2004,1,6) - ISOdate(2004,1,1))$mon
Error in (ISOdate(2004, 1, 6) - ISOdate(2004, 1, 1))$mon :
$ operator is invalid for atomic vectors
Use the function difftime
, with the argument units="hours"
: 使用函数
difftime
,参数units="hours"
:
x <- c(ISOdate(2004,1,6), ISOdate(2004,1,1))
difftime(x[1], x[2], units="hours")
Time difference of 120 hours
How did I know where to look? 我怎么知道在哪里看?
Well, start by looking at the structure of the object you get when you subtract two times: 那么,首先查看减去两次时得到的对象的结构:
str(x[1] - x[2])
Class 'difftime' atomic [1:1] 5
..- attr(*, "units")= chr "days"
So now you know you are dealing with a class of difftime
. 所以现在你知道你正在处理一类
difftime
。 From here it's easy to find help: See ?difftime
从这里可以很容易地找到帮助:参见
?difftime
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