需要将字符串列表转换为普通数字列表，字符串是基数10

Question

I have a list of integers looking like this:

["1e-04", "1e-06", "1e-08", "1e-10", "1e-12"]

I need to convert this list of strings into a list of normal numbers, but the base 10 gets me stuck. Any suggestions? Thanks.

Answer 1

>>> import ast
>>> L = ["1e-04", "1e-06", "1e-08", "1e-10", "1e-12"]
>>> [ast.literal_eval(x) for x in L]
[0.0001, 1e-06, 1e-08, 1e-10, 1e-12]

Or simply..

>>> [float(x) for x in L]
[0.0001, 1e-06, 1e-08, 1e-10, 1e-12]

Answer 2

I'd use map and float :

>>> values_as_strings = ["1e-04", "1e-06", "1e-08", "1e-10", "1e-12"
>>> values_as_floats = map(float, values_as_strings)
>>> print values_as_floats
[0.0001, 1e-06, 1e-08, 1e-10, 1e-12]

See map .

Answer 3

a=[eval(i) for i in a] # here a is the list

this list comprehension will solve it