简体   繁体   English

降价算法:字符串困难

[英]Markdown algorithm: string difficulties

I started writing this algorithm: 我开始编写此算法:

public static String convert(String str) {
    if (str.equals("# "))
        return " ";

    if (str.matches("#+.+")) {
        int n = str.length() - str.replaceFirst("#+", "").length();
        return "<h" + n + ">" + str.substring(n) + "<h" + n + ">";
    }

    return str;
}
}

So when I type, ####title, it returns < h4>title< /h4> 因此,当我键入#### title时,它将返回<h4> title </ h4>

My problem is that when I write ####title###title, I would like it to return < h4>title< /h4> < h3>title< /h3> but it only returns < h4>title< /h4>...What am I doing wrong??? 我的问题是,当我写#### title ### title时,我希望它返回<h4> title </ h4> <h3> title </ h3>,但它只返回<h4> title </ h4 > ...我在做什么错???

Thats because you are using the pattern: - #+.+ . 那是因为您使用的是模式:- #+.+

Now, since . 现在,因为. matches everything in Regex, so in the above pattern, it matches everything after an initial set of #'s . 匹配正则表达式中的所有内容,因此在上述模式中,它匹配initial set #'s之后的everything

So, for your input: - ####title###title , your pattern will match: - 因此,对于您的输入:- #### title ### title ,您的模式将匹配:-

  • #+ will match #### #+将匹配####
  • .+ will match title###title .+将匹配title###title

You need to change your regex to : - (#+[^#]+) , and probably need to use Pattern class here to get the desired output, becaues you want to match every part of your string to the given pattern . 您需要将正则表达式更改为:- (#+[^#]+) ,并且可能需要在此处使用Pattern类来获取所需的输出,因为您希望将字符串的every部分都与给定的pattern匹配。

#+[^#]+ -> Will match the first set of # and then everything after that, except # . #+[^#]+ ->将匹配第一组# ,然后匹配除#之外的所有内容。 So it stops where the next set of #'s start. 因此它停止了下一组#'s开始。

Here's how you can use it: - 使用方法如下:-

    String str = "####title###title";  // str is the method parameter
    if (str.equals("# "))
        System.out.println(" ");

    Pattern pattern = Pattern.compile("(#+[^#]+)");
    Matcher matcher = pattern.matcher(str);

    while (matcher.find()) {
        String str1 = matcher.group(1);
        int n = str1.length() - str1.replaceFirst("#+", "").length();
        System.out.println("<h" + n + ">" + str1.substring(n) + "</h" + n + ">");
    }

OUTPUT : - 输出 :-

<h4>title</h4>
<h3>title</h3>

You are replacing only the first occurrence of #+. 您只替换第一次出现的#+。 Try replacing the if with a while and instead of return inside the if, append the result into a StringBuilder. 尝试将if替换为一会儿,而不是在if内部返回,而是将结果附加到StringBuilder中。
Something like: 就像是:

String str = "####title###title2"; 
    StringBuilder sb = new StringBuilder();
    while (str.matches("#+.+")) {          
        int n = str.length() - str.replaceFirst("#+", "").length();
         str = str.replaceFirst("#+", "");
        int y = str.length();
        if(str.matches(".+#+.+")) {
            y = str.indexOf("#");
            sb.append( "<h" + n + ">" + str.substring(0,y) + "<h" + n + ">");
            str = str.substring(y, str.length());
        } else {
            sb.append( "<h" + n + ">" + str.substring(0,y) + "<h" + n + ">");
        }

    }
    System.out.println(sb.toString());

}

You are matching wrong string, try this one: 您匹配了错误的字符串,请尝试以下方法:

#+[^#]+

And of course you want to make call it recursivly or in a loop 当然,您要递归或循环调用

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM