降价算法：＃号后接Enter的序列应不返回任何内容

Question

So now I have this method:

public static String convert(String str) {

    if (str.equals("# "))
    System.out.println(" ");

Pattern pattern = Pattern.compile("(#+[^#]+)");
Matcher matcher = pattern.matcher(str);

while (matcher.find()) {
    String str1 = matcher.group(1);
    int n = str1.length() - str1.replaceFirst("#+", "").length();
System.out.println("<h" + n + ">" + str1.substring(n) + "</h" + n + ">");
}

return ("");
}    

When I type ###Le Monde # it gives me < h3>Le Monde < /h3> < h1> < /h1>. I would like it to ignore the # following "le monde". Basically, I want the algorithm to ignore a series of # followed by a space or return key. What am I doing wrong?

Answer 1

Add another line after getting the next match (str1), so:

String str1 = matcher.group(1);
if(str1.replaceFirst("#+", "").length() == 0 || str1.replaceFirst("#+", "").matches("[\\s]+")) continue;

That will ignore any whitespaces matches.