C-尝试在循环中添加比上一行更多的空间

Question

I want to add an additional space to the beginning of each new line. the current output is:

$****
 $***
  $**
   $*
    $
     Press any key to continue . . .

What I want is:

$****
 $***
  $**
   $*
    $
Press any key to continue . . .

I added the for-loop! it looks almost perfect except the "press any key to continue..." message is tabbed. How can this be fixed?

Code:

for(r=1; r<=5; r++) {
  printf("$");
  for(c=1; c<=5;c++) {
    if(6-r<=c) {
      printf(" ");
    } else {
      printf("*");
    }
  }
  printf("\n");
  n++;
  for (f=0;n>f;f++)
    {
        printf(" ");
    }
}

Answer 1

In its simplest form: just print spaces, then the '$', then the asterisks.

int r, c;
for(r=0; r<5; r++) {
  for(c=0; c<r; c++){
    printf(" ");
  }
  printf("$");
  for(c=r+1; c<5;c++) {
      printf("*");
  }
  printf("\n");
  n++;//What is this here for?
}

You can pare that down with a great printf trick (already submitted by someone else, so I won't go into it here:

int r, c;
for(r=0; r<5; r++) {
  printf("%*s", r+1, "$");
  for(c=r+1; c<5;c++) {
      printf("*");
  }
  printf("\n");
  n++;//What is this here for?
}

But wait, there's more! using a period ( . ), you can force a string to truncate, so:

int r;
for(r=1; r<6; r++) {
  printf("%*s%.*s\n", r, "$", 5-r, "*****");
}

Bam! Got the whole thing down to one statement!

Answer 2

You can use the trick of variable left-padding when you write the $ :

printf("%*s", r, "$");

The * in the string format field lets you specify a padding width.

Answer 3

Currently your n++; does nothing. To print(" ") n times you need to use something like a for loop. One way of doing this: Print the amount of spaces, Then print the amount of stars you need which should be 4 - n.

#include <stdio.h>

int main(int argc, char *argv[]) {
    int r;
    int c;
    int n = 0;
    for(r=1; r<=5; r++)
    {
        for (int i = 1; i<=n; i++) { //Print " " n number of times.
            printf(" ");
        }
        printf("$"); //Print dollar sign.
        for(c=0; c<(4-n);c++) //Print * 4-n times.
        {
            printf("*");
        }
        printf("\n");
        n++;

    }
}

Answer 4

Well you got the answer in your question itself, "how to say printf(" "); 'n' times" the easiest way to say printf 'n' times is to run it 'n' times, just like how you asked the program to print '*' (6-r) times!

well here is a very simple code to help you get the output you wanted

#include<stdio.h>
void main()
{
    int r,c,n=0;

    for(r=1; r<=5; r++)
    {
        for(c=n;c>0;c--)
        {
            printf(" ");

        }
        printf("$");
        for(c=1; c<=5;c++)
        {
            if((6-r)<=c)
            {
                printf(" ");
            }
            else
            {
                printf("*");
            }
        }

        printf("\n");
        n++;

    }
}

If you want to check out the code just go to Codepad.org here you can run your code and see the output