在扩展通用类的类中启动实例变量

Question

I have a generic class "SimpleList" (excerpt):

public abstract class SimpleList<T> {

   protected List<T> list;

   public SimpleList(List<T> list) {
      this.list = list;
   }
}

And another class "TrackList" that extends it (excerpt):

public class TrackList extends SimpleList {

    public TrackList(List<XmlTrack> list) {
        super(list);
    }
}

In "TrackList" I specify that the list is to hold objects of type "XmlTrack". It seems though, like it's not possible to get an object from that list and access its methods. For example, this won't work:

list.get(0).someMethodSpecificToXmlTrack()

I don't understand why this doesn't work? Isn't the list in "SimpleList" set to only hold "XmlTrack"s?

Answer 1

You need to define it as

public class TrackList extends SimpleList<XmlTrack> {

    public TrackList(List<XmlTrack> list) {
        super(list);
    }
}

Because SimpleList is generic, but you did not specify a type argument when you extended it.

Answer 2

May be you need

public class TrackList extends SimpleList< XmlTrack >