在 bash 中正确展开命令行参数

Question

I want to display what I'm running, but when the commands contain space parameter, it failed.我想显示我正在运行的内容，但是当命令包含空格参数时，它失败了。

#!/bin/bash
go() {
  echo "*** $*"
  $* || exit 1
}
go make NAME="Hi Here"

That will get wrong behavior like那会得到错误的行为，比如

make NAME=Hi Here

Is there any better method to improve the go() function?有没有更好的方法来改进 go() 函数？

Answer 1

Replace $* with "$@":将 $* 替换为 "$@"：

#!/bin/bash
go() {
  echo "*** $*"
  "$@" || exit 1
}
go make NAME="Hi Here"