从Notepad ++在IDLE中运行Python时打开外部文件

Question

I have two files, both on my Desktop:

sotest.py

print 'Hello world'

sotest2.py

foo = open ('sotest.py', 'r')

I'm running Python out of Notepad++ as follows (from Use IDLE to launch script using the full file path ):

C:\Program Files (x86)\Python27\Lib\idlelib\idle.bat -r "$(FULL_CURRENT_PATH)"

Running sotest2.py returns the following:

Traceback (most recent call last):
  File "C:\Users\doncherry\Desktop\sotest2.py", line 7, in <module>
    foo = open ('sotest.py', 'r')
IOError: [Errno 2] No such file or directory: 'sotest.py'

When running the same file out of Pyhton's IDLE, it runs without errors. If I change sotest2.py to the following, it works out of Notepad++ without problems.

import sotest

Which part of my configuration do I need to change to make the opening work? I'd prefer to change some setting in Notepad++ rather than adding code to each of my Python files.

Answer 1

import sotest works because it searches sotest module in sys.path and the sotest2.py 's directory is added to sys.path if you run sotest2.py as a script. If sotest2.py and sotest.py were in different directories then unless something else put sotest.py 's directory into pythonpath then import sotest inside sotest2.py would fail.

To open sotest.py inside sotest2.py as a file you could specify its absolute path. Assuming they are in the same directory you could find it automatically:

# in sotest2.py:
import os

scriptdir = os.path.dirname(os.path.abspath(__file__))
path = os.path.join(scriptdir, 'sotest.py')
with open(path) as sotest_file:
     text = sotest_file.read()