[英]xsl syntax for an xml
I have the following structure for a movies xml file 电影xml文件具有以下结构
<movies>
<movie>
<genre>Drama</genre>
<genre>Thriller</genre>
</movie>
....
</movies>
Shouldn't this snippet for selecting every value of genre for each movie tag work ? 为每个电影标签选择每个体裁值的代码片段都行不通吗?
<xsl:template match="/">
<html>
<body>
<h2>MOVIES</h2>
<table border="1">
<tr bgcolor="#9acd32">
<th>Genre</th>
</tr>
<xsl:for-each select="movies/movie">
<tr>
<td>
<xsl:for-each select="movies/movie/genre">
<xsl:value-of select="genre"/>
</xsl:for-each>
</td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
It shows nothing as ouput. 它没有显示出输出。 Can anyone please point out the mistake ? 任何人都可以指出错误吗?
It's not working because of the selector in the nested xsl:for-each
: the outer one iterates through movies/movie
, so in the inner one you already are in a movie
element, but you're selecting movies/movie/genre
; 由于嵌套的xsl:for-each
中的选择器,它不起作用:外部的一个遍历movies/movie
,因此在内部的一个中,您已经在movie
元素中,但是您正在选择movies/movie/genre
; that means you're looking for /movies/movie/movies/movie/genre
. 这意味着您正在寻找/movies/movie/movies/movie/genre
。 The xsl:value-of
uses an incorrect selector as well. xsl:value-of
使用了错误的选择器。
The code should be (untested): 该代码应(未试用):
<xsl:for-each select="movies/movie">
<tr>
<td>
<!-- context element here is movie -->
<xsl:for-each select="genre">
<!-- context element here is genre -->
<xsl:value-of select="."/>
<!-- Separate genres with a comma -->
<xsl:if test="not(position() = last())">, </xsl:if>
</xsl:for-each>
</td>
</tr>
</xsl:for-each>
By the way (off-topic), the bgcolor
attribute was deprecated in HTML 4 (a long time ago) :) You should use style
instead: 顺便说一句(离题), bgcolor
属性在HTML 4中已经过时了(很久以前):)您应该改用style
:
<tr style="background-color: #9acd32;">
While sierrasdetandil's answer already gave you the solution for your problem at hand I'd like to provide an alternative using apply-templates
instead of for-each
: 尽管sierrasdetandil的答案已经为您提供了解决您手头问题的方法,但我想提供一个替代方法,使用apply-templates
代替for-each
:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" />
<xsl:template match="/">
<html>
<body>
<h2>MOVIES</h2>
<table>
<tr><th>Genre</th></tr>
<xsl:apply-templates />
</table>
</body>
</html>
</xsl:template>
<xsl:template match="movies">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="movie">
<tr>
<td>
<xsl:apply-templates />
</td>
</tr>
</xsl:template>
<xsl:template match="genre">
<xsl:value-of select="." />
</xsl:template>
</xsl:stylesheet>
As simple as this : 就这么简单 :
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<table><xsl:apply-templates/></table>
</xsl:template>
<xsl:template match="movie">
<tr>
<xsl:apply-templates select="node()|@*"/>
</tr>
</xsl:template>
<xsl:template match="genre"><td><xsl:apply-templates/></td></xsl:template>
</xsl:stylesheet>
When this transformation is applied on the provided XML document: 在提供的XML文档上应用此转换时:
<movies>
<movie>
<genre>Drama</genre>
<genre>Thriller</genre>
</movie>
</movies>
the wanted, correct result is produced: 所需的正确结果产生了:
<table>
<tr>
<td>Drama</td>
<td>Thriller</td>
</tr>
</table>
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