在C ++中用前导零更改十六进制数的位，（C）

Question

I have this number in hex string:

002A05.

I need to set 7-th bit of this number to 1, so after conversion I will get

022A05

But it has to work with every 6 chars hex number.

I tried converting hex string to integer via strtol, but that function strip leading zeros.

Please help me how can I solve it.

Answer 1

int hex=0x002A05;
int mask = 0x020000;
printf ("%06X",hex | mask);

hope this helps

Answer 2

In a 24-bit number bit #7 (counting from the left, as you did in your example, not from the right, as is done conventionally) is always going to be in the second byte from the left. You can solve your problem without converting the entire number to integer by taking that second hex digit, converting it to a number 0..15, setting its bit #3 (again counting from the left), and converting the result back to a hex digit.

int fromHex(char c) {
    c = toupper(c);
    if (c >= '0' && c <= '9') {
        return c-'0';
    } else {
        return c-'A'+10;
    }
}
char toHexDigit(int n) {
    return n < 10 ? '0'+n : 'A'+n-10;
}

char myNum[] = "002A05";
myNum[1] = toHexDigit(fromHex(myNum[1]) | 2);
printf("%s\n", myNum);

This prints '022A05' ( link to ideone ).

Answer 3

It sounds to me like you have a string, not a hex constant, that you want to manipulate. You can do it pretty easily by bit twiddling the ascii value of the hex character. If you have char representing a hex character like char h = '6'; , char h = 'C'; , or char h = ''; , you can set the 3rd from the left (2nd from the right) bit in the number that the character represents using:

 h = h > '7' ? h <= '9' ? h + 9 : ((h + 1) | 2) - 1 : h | 2;

So you can do this to the second character (4 + 3 bits) in your string. This works for any hex string with 2 or more characters. Here is your example:

char hex_string[] = "002A05";

// Get the second character from the string
char h = hex_string[1];

// Calculate the new character
h = h > '7' ? h <= '9' ? h + 9 : ((h + 1) | 2) - 1 : h | 2;

// Set the second character in the string to the result
hex_string[1] = h;

printf("%s", hex_string); // 022A05

Answer 4

You asked about strtol specifically, so to answer your question, just add padding after you convert the number with strtol :

const char *s = "002A05";
int x = strtol(s, NULL, 16);
x |= (1<<17);
printf("%.6X\n",x);