用于从日期中提取年份的 SQL 查询

Question

I am trying to create a query that gets only the year from selected dates. Ie select ASOFDATE from PSASOFDATE; returns 11/15/2012 , but I want only 2012 . How can I get only the year? I know the YEAR function can be used, but I'm not sure how.

Answer 1

这对我有用：

SELECT EXTRACT(YEAR FROM ASOFDATE) FROM PSASOFDATE;

Answer 2

这个怎么样？

SELECT TO_CHAR(ASOFDATE, 'YYYY') FROM PSASOFDATE

Answer 3

just pass the columnName as parameter of YEAR

SELECT YEAR(ASOFDATE) from PSASOFDATE;

another is to use DATE_FORMAT

SELECT DATE_FORMAT(ASOFDATE, '%Y') from PSASOFDATE;

• SQLFiddle Demo

UPDATE 1

I bet the value is varchar with the format MM/dd/YYYY, it that's the case,

SELECT YEAR(STR_TO_DATE('11/15/2012', '%m/%d/%Y'));

• SQLFiddle Demo

LAST RESORT if all the queries fail

use SUBSTRING

SELECT SUBSTRING('11/15/2012', 7, 4)

• SQLFiddle Demo

Answer 4

SELECT date_column_name FROM table_name WHERE EXTRACT(YEAR FROM date_column_name) = 2020

Answer 5

Edit: due to post-tag 'oracle', the first two queries become irrelevant, leaving 3rd query for oracle.

For MySQL:

SELECT YEAR(ASOFDATE) FROM PASOFDATE

Editted: In anycase if your date is a String, let's convert it into a proper date format. And select the year out of it.

SELECT YEAR(STR_TO_DATE(ASOFDATE, '%d-%b-%Y')) FROM PSASOFDATE

Since you are trying Toad, can you check the following code:

For Oracle:

SELECT EXTRACT (TO_DATE(YEAR, 'MM/DD/YY') FROM ASOFDATE) FROM PSASOFDATE;

Reference: