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Python从和数组中获取元素并将其放入2D数组中

[英]Python taking elements from and array and putting them into a 2d array

I have been trying to take elements from a array and put them into a 2d array and I was wondering if there was a way to do that? 我一直在尝试从数组中获取元素并将其放入2d数组中,我想知道是否有办法做到这一点?

for example 例如

h = ['H', 'H', 'H', 'H', 'H', 'H', 'H', 'H', 'T']
a = Grid(3,3) #creates empty 2d array 

output would be 输出将是

H H H
H H H
H H T

I been doing something likes this. 我一直在做这样的事情。

for row in range(a.getHeight()):
    for col in range(a.getWidth():
        for i in range(len(h):
            a[row][col] = h[i]

but i get this as the output: 但我得到这个作为输出:

T T T
T T T
T T T

I think I might do something like this: 我想我可能会做这样的事情:

hh = iter(h)
for row in range(a.getHeight()):
    for col in range(a.getWidth()):
         a[row][col] = next(hh)

This assumes that you declared a properly. 这是假设你宣布a正确。 In other words, a is NOT a list set up as follows: 换句话说, a 不是按以下方式设置的列表:

a = [[None]*ncol]*nrow

That doesn't work since a would hold a bunch of references to the same inner list . 那是行不通的,因为a会包含一堆对同一内部列表的引用。 Of course, your a isn't a simple list since it has getHeight and getWidth , so I assume whatever type of object it has taken care of that already. 当然,您的a不是一个简单的列表,因为它具有getHeightgetWidth ,所以我假设它已经处理了任何类型的对象。


If you're using numpy , this becomes almost trivial: 如果您使用的是numpy ,这将变得微不足道:

h = np.array(['H', 'H', 'H', 'H', 'H', 'H', 'H', 'H', 'T'])
a = h.reshape((3,3)) 

use a list comprehension: 使用列表理解:

In [11]: h = ['H', 'H', 'H', 'H', 'H', 'H', 'H', 'H', 'T']

In [12]: [h[i:i+3] for i in range(0,len(h),3)]
Out[12]: [['H', 'H', 'H'], ['H', 'H', 'H'], ['H', 'H', 'T']]

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