计算每个句子中有多少个单词

Question

I'm stuck on how to count how many words are in each sentence, an example of this is: string sentence = "hello how are you. I am good. that's good." and have it come out like:

//sentence1: 4 words
//sentence2: 3 words
//sentence3: 2 words

I can get the number of sentences

    public int GetNoOfWords(string s)
    {
        return s.Split(new char[] { '.' }, StringSplitOptions.RemoveEmptyEntries).Length;
    }
    label2.Text = (GetNoOfWords(sentance).ToString());

and i can get the number of words in the whole string

    public int CountWord (string text)
    {
        int count = 0;
        for (int i = 0; i < text.Length; i++)
        {
            if (text[i] != ' ')
            {
                if ((i + 1) == text.Length)
                {
                    count++;
                }
                else
                {
                    if(text[i + 1] == ' ')
                    {
                        count++;
                    }
                }
            } 
        }
        return count;
    }

then button1

        int words = CountWord(sentance);
        label4.Text = (words.ToString());

But I can't count how many words are in each sentence.

Answer 1

Instead of looping over the string as you do in CountWords I would just use;

 int words = s.Split(' ').Length;

It's much more clean and simple. You split on white spaces which returns an array of all the words, the length of that array is the number of words in the string.

Answer 2

Why not use Split instead?

 var sentences = "hello how are you. I am good. that's good."; foreach (var sentence in sentences.TrimEnd('.').Split('.')) Console.WriteLine(sentence.Trim().Split(' ').Count());

Answer 3

If you want number of words in each sentence, you need to

string s = "This is a sentence. Also this counts. This one is also a thing.";
string[] sentences = s.Split(new char[] { '.' }, StringSplitOptions.RemoveEmptyEntries);
foreach(string sentence in sentences)
{
    Console.WriteLine(sentence.Split(' ').Length + " words in sentence *" + sentence + "*");
}

Answer 4

Use CountWord on each element of the array returned by s.Split:

string sentence = "hello how are you. I am good. that's good.";
string[] words = sentence.Split(new char[] { '.' }, StringSplitOptions.RemoveEmptyEntries).Length;

for (string sentence in sentences)
{
    int noOfWordsInSentence = CountWord(sentence);
}

Answer 5

string text = "hello how are you. I am good. that's good.";
string[] sentences = s.Split(new char[] { '.' }, StringSplitOptions.RemoveEmptyEntries);
IEnumerable<int> wordsPerSentence = sentences.Select(s => s.Trim().Split(' ').Length);

Answer 6

As noted in several answers here, look at String functions like Split, Trim, Replace, etc to get you going. All answers here will solve your simple example, but here are some sentences which they may fail to analyse correctly;

"Hello, how are you?" (no '.' to parse on)
"That apple costs $1.50."  (a '.' used as a decimal)
"I   like     whitespace    .    "   
"Word"  

Answer 7

If you only need a count, I'd avoid Split() -- it takes up unnecessary space. Perhaps:

static int WordCount(string s)
{
    int wordCount = 0;
    for(int i = 0; i < s.Length - 1; i++)
        if (Char.IsWhiteSpace(s[i]) && !Char.IsWhiteSpace(s[i + 1]) && i > 0)
            wordCount++;
    return ++wordCount;
}

public static void Main()
{
    Console.WriteLine(WordCount(" H elloWor    ld g  ")); // prints "4"
}

It counts based on the number of spaces (1 space = 2 words). Consecutive spaces are ignored.

Answer 8

Does your spelling of sentence in:

int words = CountWord(sentance);

have anything to do with it?