用数据填充Shell脚本数组

Question

I want to extract some data from a file and save it in an array, but i don't know how to do it.

In the following I'm extracting some data from /etc/group and save it in another file, after that I print every single item:

awk -F: '/^'$GROUP'/ { gsub(/,/,"\n",$4) ; print $4 }' /etc/group > $FILE

for i in `awk '{ print $0 }' $FILE`
   do
     echo "member: "$i" "
   done 

However, I don't want to extract the data into a file, but into an array.

Answer 1

members=( $(awk -F: '/^'$GROUP':/ { gsub(/,/,"\n",$4) ; print $4 }' /etc/group) )

The assignment with the parentheses indicates that $members is an array. The original awk command has been enclosed in $(...) , and the colon added so that if you have group and group1 in the file, and you look for group , you don't get the data for group1 too. Of course, if you wanted both entries, then you drop the colon I added.

Answer 2

j=0
for i in `awk '{ print $0 }' $FILE`
do
  arr[$j] = $i
  j=`expr $j + 1`
done 

Answer 3

arr=($(awk -F: -v g=$GROUP '$1 == g { gsub(/,/,"\n",$4) ; print $4 }' /etc/group))