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从另一个类中修改对象的std :: vector

[英]modifying an object's std::vector from within another class

Intro: 介绍:

In my program, a group object has an std::vector full of polygons (a ring and holes) and a polygon object has an std::vector of points. 在我的程序中, group对象的std::vector充满了多边形(一个圆环和孔),而polygon对象的点则是std::vector In reality, the classes are more complicated, I've stripped them down here to illustrate my problem. 实际上,这些类更为复杂,我在这里将它们简化了下来以说明我的问题。

The problem: 问题:

I want to be able to modify the point 'sx and y coordinates from within it's corresponding group object. 我希望能够从其相应的组对象中修改point 'sx和y坐标。 Below, in group.cpp , I have a dummy function called void Group::tryChangingAllX() that tries to accomplish this. 下面,在group.cpp ,我有一个名为void Group::tryChangingAllX()的虚拟函数,试图完成此任务。 However, calling show() on the group afterwards shows no change to it's polygon's point's coordinates. 但是,随后在组上调用show()并不会改变其多边形点的坐标。

I think I need to use references/pointers, but I need a nudge in the right direction. 我想我需要使用引用/指针,但是我需要朝着正确的方向轻推。

point.cpp: point.cpp:

#include "point.h"
#include <iostream>
Point::~Point(){}
Point::Point(int x, int y){
    _x = x;
    _y = y;
}
void Point::show(){std::cout << "(" << x() << "," << y() << ")";}
void Point::x(int x){_x = x;}
void Point::y(int y){_y = y;}
int Point::x(){return _x;}
int Point::y(){return _y;}

point.h: point.h:

#ifndef POINT_GUARD
#define POINT_GUARD
class Point{
    int _x;
    int _y;
    public:
        Point(int x, int y);
        ~Point();
        void show();
        int x();
        int y();
        void x(int x);
        void y(int y);  
};
#endif

polygon.cpp: polygon.cpp:

#include "polygon.h"
#include "point.h"
#include <iostream>
#include <vector>

Polygon::~Polygon(){}
Polygon::Polygon(){}
std::vector<Point> Polygon::points(){return _points;}
Polygon::Polygon(std::vector<Point> points){_points = points;}
void Polygon::show(){
    std::cout << "Points: ";
    for(std::vector<Point>::size_type i = 0; i != _points.size(); i++) {
        _points[i].show();
    }
}

polygon.h: polygon.h:

#ifndef POLYGON_GUARD
#define POLYGON_GUARD

#include <vector>
#include "point.h"

class Polygon{
    //private:
    std::vector<Point> _points;
    public:
        ~Polygon();
        Polygon ();
        Polygon(std::vector<Point> points);
        std::vector<Point> points();
        void show();
};
#endif

group.cpp: group.cpp:

#include <iostream>
#include <vector>
#include "group.h"
#include "polygon.h"
Group::~Group(){}
Group::Group(std::vector<Polygon> polygons){
    _ring = polygons.front();
    polygons.erase(polygons.begin());
    _holes = polygons;
}
void Group::tryChangingAllX(){
    std::vector<Point> points = _ring.points();
    for(std::vector<Point>::size_type i = 0; i != points.size(); i++) {
        points[i].x(15);
    }
}
void Group::show(){
    _ring.show();
    if(_holes.size()>0){
        for(std::vector<Polygon>::size_type i = 0; i != _holes.size(); i++) {
            _holes[i].show();
        }
    }
}

group.h: group.h:

#ifndef GROUP_GUARD
#define GROUP_GUARD

#include <vector>
#include "polygon.h"

class Group{
    Polygon _ring;
    std::vector<Polygon> _holes;
    public:
        ~Group();
        Group(std::vector<Polygon> polygons);
        void show();
        void tryChangingAllX();

};
#endif

Thanks! 谢谢!

The function 功能

std::vector<Point> points();

returns by value , so when you call it, you get a copy of the member. 按值返回,因此在调用它时,将获得该成员的副本。 You need to change it to 您需要将其更改为

std::vector<Point>& points();

After you've done this 完成此操作后

std::vector<Point> points = _ring.points();

also makes a copy of the returned value. 还会复制返回值。 To refer to the actual member in _ring , change to: 要引用_ring的实际成员,请更改为:

std::vector<Point>& points = _ring.points();

That should do it. 那应该做。

Note that you should pass std::vector by const reference to prevent an un-necessary copy: 请注意,应通过const引用传递std::vector ,以防止不必要的复制:

Polygon(const std::vector<Point>& points); 

and consider making methods that don't modify the class const : 并考虑制作不修改类const

int x() const;  

This is exactly your problem - you're getting a copy of your points rather than working on a reference to the original points themselves. 这正是您的问题-您得到的是点的副本 ,而不是对原始点本身的引用

polygon.cpp: polygon.cpp:

return points by reference not value: 返回点按引用而不是值:

std::vector<Point>& Polygon::points(){return _points;} // note the '&' in the return

group.cpp: group.cpp:

obtain a reference to the points, not a copy 获得要点的参考 ,而不是副本

std::vector<Point>& points = _ring.points(); // note the '&' in what you're getting

Answers posted by Luchian and lori are technically correct. Luchian和lori发布的答案在技术上是正确的。 But there are design considerations that I want to point out. 但是,我要指出一些设计注意事项。

Returning a reference will allow anyone to modify private parts of Polygon object. 返回reference将允许任何人修改Polygon对象的private部分。 By design you only want Group class to do this. 通过设计,您只希望Group类这样做。 Consider making Group a friend of Polygon . 考虑让Group成为Polygonfriend Group then will have access to private bits of Polygon . 然后, Group将可以访问Polygon私有位。 This will ensure a tighter encapsulation overall. 这将确保整体封装更紧密。

In polygon.h polygon.h中

friend class Group;

In group.cpp group.cpp中

void Group::tryChangingAllX()
{
    for(std::vector<Point>::size_type i = 0; i != _ring._points.size(); i++)
    {
        _ring._points[i].x(15);
    }
}

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