[英]I have an 'n' number of array and how can I concat all array into a single array using jQuery
How can I concat 'n' number of arrays into a single array using jQuery. 我如何使用jQuery将n个数组合并为一个数组。
a1 = [a,b,c,d,f];
a2 = [h,g,f,r];
...............
an = [r,e,c,g,s,g];
and I need to get like 我需要变得像
A = [a,b,c,d,f,h,g,f,r,.....,r,e,c,g,s,g];
Please help. 请帮忙。 Thank you in advance for all replay
预先感谢您的所有重播
You're looking for array concat
method 您正在寻找
array concat
方法
var arr1 = ["a", "b"];
var arr2 = ["c", "d"];
var arr3 = arr1.concat(arr2);
console.log(arr3); // ["a", "b", "c", "d"]
You can find more info here: 您可以在此处找到更多信息:
https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Array/concat https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Array/concat
var A=a1.concat(a2,a3,a4,....,an);
Assuming your arrays are all named a<x>
, and global variables, you can loop through them on the window object as follows: 假设所有数组均名为
a<x>
和全局变量,则可以在window对象上循环遍历它们,如下所示:
var output = [];
for(var i = 1; window['a'+i]; i++){
output = output.concat(window['a'+i]);
}
Output will then, at the end of the loop, be a concatenation of all the arrays. 然后,在循环结束时,输出将是所有数组的串联。
window['a'+i]
will refer to the a1 - aX
arrays, since global variables are properties of the window
object. window['a'+i]
将引用a1 - aX
数组,因为全局变量是window
对象的属性。 As such, these are all identical: 因此,这些都是相同的:
var output = "Some content"
console.log(output);
console.log(window.output);
console.log(window['output']);
// These will all return "Some content"
You can also manually concatenate them like this if you know how many you have: 如果您知道有多少个,也可以像这样手动连接它们:
output = a1.concat(a2,a3,a<x>...);
Array.prototype.concat([1,2,3],[4,5])
要么
[1,2,3].concat([4,5])
Try with $.merge; 尝试$ .merge; example:
例:
var new = $.merge( [0,1,2], [2,3,4] ); // new = [0,1,2,2,3,4]
Use concat()
method. 使用
concat()
方法。
var a1 = ["a","b","c","d","f"];
var a2 = ["h","g","f","r"]
var a3 = a1.concat(a2);
console.log(a3); // Outputs: ["a", "b", "c", "d", "f", "h", "g", "f", "r"]
您可以使用标准功能concat
。
Something similar to: 类似于:
for(a2...an){
a1 = $.merge(a1,next);
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.