如何将字符串添加到文件中每一行的开头？

Question

I have the following bash code which loops through a text file, line by line.. im trying to prefix the work 'prefix' to each line but instead am getting this error:

rob@laptop:~/Desktop$ ./appendToFile.sh stusers.txt kp
stusers.txt
kp
./appendToFile.sh: line 11: /bin/sed: Argument list too long
115000_210org@house.com,passw0rd

This is the bash script..

#!/bin/bash

file=$1
string=$2

echo "$file"
echo "$string"

for line in `cat $file`
do
    sed -e 's/^/prefix/' $line
    echo "$line"
done < $file

What am i doing wrong here?

Update: Performing head on file dumps all the lines onto a single line of the terminal, probably related?

rob@laptop:~/Desktop$ head stusers.txt
rob@laptop:~/Desktop$ ouse.com,passw0rd

Answer 1

一行awk命令也可以做到这一点：

awk '{print "prefix" $0}' file

Answer 2

Concerning your original error:

./appendToFile.sh: line 11: /bin/sed: Argument list too long

The problem is with this line of code:

sed -e 's/^/prefix/' $line

$line in this context is file name that sed is running against. To correct your code you should fix this line as such:

echo $line | sed -e 's/^/prefix/'

(Also note that your original code should not have the < $file at the end.)

William Pursell addresses this issue correctly in both of his suggestions.

However, I believe you have correctly identified that there is an issue with your original text file. dos2unix will not correct this issue, as it only strips the carriage returns Windows sticks on the end of lines. (However, if you are attempting to read a Linux file in Windows, you would get a mammoth line with no returns.)

Assuming that it is not an issue with the end of line characters in your text file, William Pursell's, Andy Lester's, or nullrevolution's answers will work.

A variation on the while read... suggestion:

while read -r line; do  echo "PREFIX " $line; done < $file

This could be run directly from the shell (no need for a batch / script file):

while read -r line; do echo "kp" $line; done < stusers.txt

Answer 3

整个循环可以由对整个文件进行操作的单个sed命令替换：

sed -e 's/^/prefix/' $file

Answer 4

A Perl way to do it would be:

perl -p -e's/^/prefix' filename

or

perl -p -e'$_ = "prefix $_"' filename

In either case, that reads from filename and prints the prefixed lines to STDOUT.

If you add a -i flag, then Perl will modify the file in place. You can also specify multiple filenames and Perl will magically do all of them.

Answer 5

Instead of the for loop, it is more appropriate to use while read... :

while read -r line; do
do
    echo "$line" | sed -e 's/^/prefix/'
done < $file

But you would be much better off with the simpler:

sed -e 's/^/prefix/' $file

Answer 6

Use sed. Just change the word prefix .

sed -e 's/^/prefix/' file.ext

If you want to save the output in another file

sed -e 's/^/prefix/' file.ext > file_new.ext

Answer 7

You don't need sed, just concatenate the strings in the echo command

while IFS= read -r line; do
    echo "prefix$line"
done < filename

Your loop iterates over each word in the file:

for line in `cat file`; ...

Answer 8

sed -i '1a\
Your Text' file1 file2 file3

Answer 9

A solution without sed/awk and while loops:

xargs -n1 printf "$prefix%s" < "$file"